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Ipatiy [6.2K]
2 years ago
9

The reaction 2NO + O2 → 2NO2 is third order. Assuming that a small amount of NO3 exists in rapid reversible equilibrium with NO

and O2 and that the rate-determining step is the slow biomelcular reaction NO3 + NO → 2NO2, derive the rate equation for this mechanism

Chemistry
1 answer:
Rina8888 [55]2 years ago
5 0

Answer:

The equation for the rate of this reaction is R = [NO] + {O2}

Explanation:

The rate-determining step of a reaction is the slowest step of a chemical reaction which determines the rate (speed) at which the overall reaction would take place.

Reaction mechanism:

The slow and fast reactions both have NO3 which is cancelled out on both sides, in order to get the overall reaction.

The rate law for this reaction would be that for the rate determining step:

R = [NO] + {O2}

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Fill in the blanks to determine the number of protons and electrons in an oxygen ion. (consult the periodic table to determine t
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Larisa pumps up a soccer ball until it has a gauge pressure of 61 kilopascals. The volume of the ball is 5.2 liters. The air tem
Nuetrik [128]
<h3>Answer:</h3>

B.  0.33 mol

<h3>Explanation:</h3>

We are given;

Gauge pressure, P = 61 kPa (but 1 atm = 101.325 kPa)

                               = 0.602 atm

Volume, V = 5.2 liters

Temperature, T = 32°C, but K = °C + 273.15

thus, T = 305.15 K

We are required to determine the number of moles of air.

We are going to use the concept of ideal gas equation.

  • According to the ideal gas equation, PV = nRT, where P is the pressure, V is the volume, R is the ideal gas constant, (0.082057 L.atm mol.K, n is the number of moles and T is the absolute temperature.
  • Therefore, to find the number of moles we replace the variables in the equation.
  • Note that the total ball pressure will be given by the sum of atmospheric pressure and the gauge
  • Therefore;
  • Total pressure = Atmospheric pressure + Gauge pressure  

       We know atmospheric pressure is 101.325 kPa or 1 atm

Total ball pressure = 1 atm + 0.602 atm

                               = 1.602 atm

That is;

PV = nRT

n = PV ÷ RT

therefore;

n = (1.602 atm× 5.2 L) ÷ (0.082057 × 305.15 K)

  = 0.3326 moles

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Therefore, there are 0.33 moles of air in the ball.

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