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Ipatiy [6.2K]
2 years ago
9

The reaction 2NO + O2 → 2NO2 is third order. Assuming that a small amount of NO3 exists in rapid reversible equilibrium with NO

and O2 and that the rate-determining step is the slow biomelcular reaction NO3 + NO → 2NO2, derive the rate equation for this mechanism

Chemistry
1 answer:
Rina8888 [55]2 years ago
5 0

Answer:

The equation for the rate of this reaction is R = [NO] + {O2}

Explanation:

The rate-determining step of a reaction is the slowest step of a chemical reaction which determines the rate (speed) at which the overall reaction would take place.

Reaction mechanism:

The slow and fast reactions both have NO3 which is cancelled out on both sides, in order to get the overall reaction.

The rate law for this reaction would be that for the rate determining step:

R = [NO] + {O2}

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7. How many moles of argon are there in 20.0 L, at 25 degrees Celsius and 96.8 kPa?
suter [353]
<h3>Answer:</h3>

              0.8133 mol

<h3>Solution:</h3>

Data Given:

                 Moles  =  n  =  ??

                 Temperature  =  T  =  25 °C + 273.15  =  298.15 K

                  Pressure  =  P  =  96.8 kPa  =  0.955 atm

                  Volume  =  V  =  20.0 L

Formula Used:

Let's assume that the Argon gas is acting as an Ideal gas, then according to Ideal Gas Equation,

                  P V  =  n R T

where;  R  =  Universal Gas Constant  =  0.082057 atm.L.mol⁻¹.K⁻¹

Solving Equation for n,

                  n  =  P V / R T

Putting Values,

                  n  =  (0.955 atm × 20.0 L) ÷ (0.082057 atm.L.mol⁻¹.K⁻¹ × 298.15 K)

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2 years ago
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A 0.500 g sample of tin (Sn) is reacted with oxygen to give 0.534 g of product. What is the empirical formula of the oxide?
REY [17]

Answer:

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Explanation:

Hello,

In this case, given that the mass of the product is 0.534 g, we can infer that the percent composition of tin is:

\%Sn=\frac{0.500g}{0.534g}*100\%\\ \\\%Sn=93.6\%

Therefore, the percent composition of oxygen is 6.4% for a 100% in total. Thus, with such percents we compute the moles of each element in the oxide:

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In such a way, for finding the smallest whole number we divide the moles of both tin and oxygen by the moles of oxygen as the smallest moles:

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Sn_2O

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