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schepotkina [342]
2 years ago
15

A bottle of antiseptic hydrogen peroxide (H2O2) is labeled 3.0% (v/v). How many mL H2O2 are in a 400.0 mL bottle of this solutio

n?
Use this formula: Percent by volume: volume of solute/volume of solution×100%
Chemistry
1 answer:
PolarNik [594]2 years ago
6 0

Answer:

= 12 mL H202

Explanation:

Given that, the concentration of H2O2 is given antiseptic = 3.0 % v/v

It implies that, 3ml  H2O2 is present in 100 ml of solution.

Therefore, to calculate the amount of H202 in 400.0 mL bottle of solution;

we have;

 (3.0 mL/ 100 mL) × 400 mL

= 12 mL H202

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A solution has a concentration of 0.6mol/dm³. If a container of this solution holds 3 moles of solute, what volume of solution i
FinnZ [79.3K]

Answer: 3 moles solute x  1 dm^3/0.60 moles solute = 5 dm^3

Explanation:

6 0
1 year ago
N2 and H2 are mixed in 14:3 mass ratio. After certain time ammonia was found to be 40% by mol. The mole fraction of N2 at that t
son4ous [18]

Answer : The mole fraction of nitrogen will be 0.4615.


Explanation : When nitrogen (N_{2})and hydrogen (H_{2})are mixed, the mole ratio becomes 1 : 1.5,


Now we know that (H_{2}) is acting as a limiting agent.


So at the time of when 0.4 moles of (NH_{3}) is been formed it requires 0.4 moles of (N_{2}) and 3.4 moles of (H_{2})


So, we find the the remaining (N_{2}) will be 0.6 and

(H_{2}) will be 0.3 mole present in mixture.


So, the mole fraction of (N_{2}) becomes = 0.6 / (0.6 + 0.4 + 0.3) Which becomes = 0.4615

8 0
2 years ago
Read 2 more answers
If a dozen apples has a mass of 2.0 kg and 0.20 bushel is 1 dozen apples, How many bushels of apples are in 1.0 Kg of apples
Maslowich

If 1 dozen apples has a mass of 2.0 kg and 0.20 bushel is 1 dozen apples, how many bushels of apples are in 1.0 kg of apples?

0.1 bushels

7 0
1 year ago
Calculate the wavelength of the photon emitted when an electron makes a transition from n=6 to n=3. You can make use of the foll
Angelina_Jolie [31]

<u>Answer:</u> The wavelength of light is 1.094\times 10^{-6}m

<u>Explanation:</u>

To calculate the wavelength of light, we use Rydberg's Equation:

\frac{1}{\lambda}=R_H\left(\frac{1}{n_f^2}-\frac{1}{n_i^2} \right )

Where,

\lambda = Wavelength of radiation

R_H = Rydberg's Constant  = 1.097\times 10^7m^{-1}

n_f = Final energy level = 3

n_i = Initial energy level = 6

Putting the values in above equation, we get:

\frac{1}{\lambda }=1.097\times 10^7m^{-1}\left(\frac{1}{3^2}-\frac{1}{6^2} \right )\\\\\lambda =\frac{1}{914617m^{-1}}=1.094\times 10^{-6}m

Hence, the wavelength of light is 1.094\times 10^{-6}m

6 0
2 years ago
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