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1 year ago

At a temperature of __________ °c, 0.444 mol of co gas occupies 11.8 l at 889 torr.

Chemistry

2 answers:

shtirl [24]1 year ago

4 0

Answer: $106^0C$

Explanation: IDEAL GAS LAW

$PV=nRT$

where,

P = pressure of the gas = 889 torr = 1.17 atm (1 torr=0.0013atm)

V = volume of the gas = 11.8 L

T = temperature of the gas = ? K

n = number of moles of gas = 0.444

R = Gas constant = 0.0821 Latm/moleK

$1.17\times 11.8=0.444\times 0.0821\times T$

$T=379K$

$T=(379-273)^0C=106^0C$

Thus temperature of gas is $106^0C$

Novay_Z [31]1 year ago

3 0

<span>ideal gas law is: PV = nRT P = pressure (torr) = 889 torr V = volume (Liters) = 11.8 L n = moles of gas = 0.444 mol R = gas constant = 62.4 (L * torr / mol * k) solve for T (in kelvin) T = PV/nR T = (889*11.8)/(.444*62.4) T = 378.6 K convert to C (subtract 273) T = 105.6 deg C</span>

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1 year ago

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1 year ago

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Regards!

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1 year ago