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andrew-mc [135]

2 years ago

8

identify A and B, isomers of molecular formula C3H4Cl2, from the given 1H NMR data: Compound A exhibits peaks at 1.75 (doublet,

3 H, J = 6.9 Hz) and 5.89 (quartet, 1 H, J = 6.9 Hz) ppm. Compound B exhibits peaks at 4.16 (singlet, 2 H), 5.42 (doublet, 1 H, J = 1.9 Hz), and 5.59 (doublet, 1 H, J = 1.9 Hz) ppm.

1 answer:

siniylev [52]2 years ago

3 0

Answer:

See explaination

Explanation:

please kindly see attachment for the step by step solution of the given problem.

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When an alpha particle is emitted from an unstable nucleus, the atomic mass numberof the nucleus

barxatty [35]

Answer:

The correct option is D.

Explanation:

Radioactive substances usually emit different types of particles when they are decaying. Such particles include alpha particles, beta particles and gamma ray. When an alpha particle is emitted from an unstable radioactive nucleus such nucleus usually lost an atomic mass that correspond to that of helium atom. Note that an alpha particle is made up of two protons and two neutrons, which result in mass number of 4. Thus, a nucleus that emit an alpha particle will have its mass number (atomic mass) reduce by 4 and atomic number that is reduced by 2.

3 0

2 years ago

Find the de Broglie wavelength lambda for an electron moving at a speed of 1.00 \times 10^6 \; {\rm m/s}. (Note that this speed

masya89 [10]

(A) $7.28\cdot 10^{-10} m$

The De Broglie wavelength of an electron is given by

$\lambda=\frac{h}{p}$ (1)

where

h is the Planck constant

p is the momentum of the electron

The electron in this problem has a speed of

$v=1.00\cdot 10^6 m/s$

and its mass is

$m=9.11\cdot 10^{-31} kg$

So, its momentum is

$p=mv=(9.11\cdot 10^{-31} kg)(1.00\cdot 10^6 m/s)=9.11\cdot 10^{-25}kg m/s$

And substituting into (1), we find its De Broglie wavelength

$\lambda=\frac{6.63\cdot 10^{-34}Js}{9.11\cdot 10^{-25} kg m/s}=7.28\cdot 10^{-10} m$

(B) $1.16\cdot 10^{-34}m$

In this case we have:

m = 0.143 kg is the mass of the ball

v = 40.0 m/s is the speed of the ball

So, the momentum of the ball is

$p=mv=(0.143 kg)(40.0 m/s)=5.72 kg m/s$

And so, the De Broglie wavelength of the ball is given by

$\lambda=\frac{h}{p}=\frac{6.63\cdot 10^{-34} Js}{5.72 kg m/s}=1.16\cdot 10^{-34}m$

(C) $9.02\cdot 10^{-9}m$

The location of the first intensity minima is given by

$y=\frac{L\lambda}{a}$

where in this case we have

$y=0.492 cm = 4.92\cdot 10^{-3} m$

L = 1.091 is the distance between the detector and the slit

$a=2.00\mu m=2.00\cdot 10^{-6}m$ is the width of the slit

Solving the formula for $\lambda$ , we find the wavelength of the electrons in the beam:

$\lambda=\frac{ya}{L}=\frac{(4.92\cdot 10^{-3}m)(2.00\cdot 10^{-6} m)}{1.091 m}=9.02\cdot 10^{-9}m$

(D) $7.35\cdot 10^{-26}kg m/s$

The momentum of one of these electrons can be found by re-arranging the formula of the De Broglie wavelength:

$p=\frac{h}{\lambda}$

where here we have

$\lambda=9.02\cdot 10^{-9}m$ is the wavelength

Substituting into the formula, we find

$p=\frac{6.63\cdot 10^{-34}Js}{9.02\cdot 10^{-9}m}=7.35\cdot 10^{-26}kg m/s$

7 0

2 years ago

Consider the equilibrium reaction: 3CIO-(aq) ↔ CIO3-(aq) + 2CI-(aq) The equilibrium constant Kc = 3.2 x 103. The following conce

blagie [28]

Answer:

Forward direction

Explanation:

The reaction quotient of an equilibrium reaction measures relative amounts of the products and the reactants present during the course of the reaction at particular point in the time.

Q < Kc , reaction will proceed in forward direction.

Q > Kc , reaction will proceed in backward direction.

Q = Kc , reaction at equilibrium.

It is the ratio of the concentration of the products and the reactants each raised to their stoichiometric coefficients. The concentration of the liquid and the gaseous species does not change and thus is not written in the expression.

Thus, for the reaction:

$3CIO^{-}_{(aq)}\rightleftharpoons CIO_3^{-}_{(aq)}+2Cl^{-}$

The expression is:

$Q=\frac {[CIO_3^{-}][Cl^{-}]^2}{[CIO^{-}]^3}$

Given,

[Cl⁻] = 0.50 mol/L; [ClO₃⁻] = 0.32 mol/L; [ClO⁻] = 0.24 mol/L

So,

$Q=\frac{0.32\times (0.50)^2}{(0.24)^3}$

Q = 5.7870

Since, Q < Kc ( $3.2\times 10^3$ )

The reaction will go in forward direction.

6 0

2 years ago

The concentration of sugar in a soft drink is measured to be 10.5%. how many grams of sugar are in 125 g of the drink?

viva [34]

The grams of the sugar in 125 g of the drink is calculated as below

%M/m) = mass of the solute (sugar)/ mass of the solvent(drink) x100

let the mass of the solute(sugar) be represented by y

convert % into fraction by dividing by 100 = 10.5/100

10.5/100 = y/125

by cross multiplication

100y =1312.5
divide both side by 100

y=13.125 grams

5 0

2 years ago

For the reaction 2Fe+3Cl2=2FeCl3

Butoxors [25]

The question is incomplete but the full question may be found in other sources.

This is the complete question:

For the reaction 2Fe + 3Cl₂ → 2FeCl₃ which option is more accurate?

a. FeCl₃, reducing agent; Fe, oxidizing agent.

b. Cl₂, oxidising agent; Fe reducing agent.

c. Fe, reducing agent; FeCl₃, oxidizing agent.

d. FeCl₃, oxidizing agent, Cl₂, reducing agent.

Answer:

<em><u>Option b. Cl₂, oxidising agent; Fe reducing agent.</u></em>

Explanation:

It is easy to recognize by simple inspection that the given reaction is a redox one (oxidation - reduction) because the substances in the reactant side are pure elements (whose oxidation state is always zero) and the substance in the product side is a compound formed by the two reactant elements (which means that now they have a different oxidation state).

In a redox reaction, <u>the element that increases its oxidation number</u> loses electrons and reduces other element, so this <u>is the reducing agent</u>. On the other hand, <u>the element whose oxidation number is decreased</u> has gained electrons, a so it <u>is the oxidizing agent</u> (it oxidizes other element).

I will show the oxidation states of each species in the chemical reaction, using superscripts:

Fe⁰ + 3Cl₂⁰ → 2 Fe⁺³Cl₃⁻¹

Thus:

2 atoms of Fe increased their oxidation number from 0 to +3; meaning that they lost 6 electrons (3 electrons each), so Fe is the reducing agent (it reduced the Cl atoms).

6 atoms of Cl decreased their oxidation number from 0 to -1; meaning that they gained 6 electrons in total (1 elecron each), so Cl is the oxidizing agent (it oxidized the Fe atoms).

6 0

2 years ago