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olga55 [171]
2 years ago
11

A 6.50-g sample of copper metal at 25.0 °c is heated by the addition of 84.0 j of energy. the final temperature of the copper i

s __________°c. the specific heat capacity of copper is
Chemistry
1 answer:
anzhelika [568]2 years ago
3 0
The final temperature of the copper is 59.0. The specific heat capacity of copper is 0.38 j/g -k
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Molecular bromine is 24 percent dissociated at 1600 k and 1.00 bar in the equilibrium br2 (
dlinn [17]
Br2 == 2Br

24% dissociated => n total moles, 0.24 mol*n of Br, and 0.76*n mol of Br2

=> partial pressure of Br, P Br = 0.24 bar, and
     partical pressure of Br2, P Br2 = 0.76 bar

kp = (P Br)^2 / P Br2 = (0.24)^2 / 0.76 = 0.0758


3 0
2 years ago
A solution is prepared by diluting 50.00 ml of 2.575 m solution of hno3 to 250.0 ml. what is the molarity of the resulting solut
larisa [96]
Thank you for posting your question here at brainly. Below are the choices that can be found elsewhere:

12.88 M 
<span>0.1278 M </span>
<span>0.2000 M </span>
<span>0.5150 M
</span>
Below is the answer:

<span>5 times diluted (250/50),so 2.575/5=0.515 M
</span>
I hope it helps. 
8 0
2 years ago
Read 2 more answers
Assume the atomic mass of element X is 22.99 amu. A 17.15−g sample of X combines with 14.17 g of another element Y to form a com
Alenkasestr [34]
The formula of the compound is XY. This means that the relation between the moles is 1: 1. One mole of X per one mole of Y.

From the information about the element X you can determine the number of moles of X (which is the same that the number of moles of Y).

# of moles of X = weigth of X / atomic mass of X = 17.15 g / 22.9 g/mol = 0.74598

Now the atomic mass of Y = weight of Y / # of moles of Y = 14.17 g / 0.74598 mol = 19 amu
8 0
2 years ago
CuSO4(aq) + 2NaOH(aq) Cu(OH)2(s) + Na2SO4(aq)
REY [17]
Your answer is right.

Important elements to consider:

- to use the balanced equation (which you did)
- divide the masses of each compound by the correspondant molar masses (which you did)
- compare the theoretical proportions with the current proportions

Theoretical: 2 mol of Na OH : 1 mol of CuSO4
Then 4 mol of NaOH need 2 mol of CUSO4.

Given that you have more than 2 mol of of CUSO4 you have plenty of it and the NaOH will consume first, being this the limiting reagent.

6 0
2 years ago
If a 100.-g sample of platinum metal has a volume of 4.67 ml, what is the density of platinum in g/cm3?
Mariulka [41]
The density of any substance does not change at a certain temperature and pressure. Even though mass and volume are intensive properties (depends on the amount of substance), density is not. It is merely a fixed ratio of mass to volume. Therefore, the solution is

Density = Mass/Volume
For your information, quantitatively, cm³ is equivalent to mL.
Density = 100 g/4.67 cm³ = 21.41 g/cm³
7 0
2 years ago
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