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user100 [1]
1 year ago
11

Which of the following is not an example of temperature abuse ?

Chemistry
2 answers:
AnnyKZ [126]1 year ago
6 0
The following of what exactly?
docker41 [41]1 year ago
4 0
I’m not sure but I think food is not reheated enough to kill the pathogens
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A 500 gram cube of lead is heated from 25 °C to 75 °C. How much energy was required to heat the lead? The specific heat of lead
Ludmilka [50]

Answer:

The energy required is 3225 Joules.

Explanation:

Given,

mass of lead cube = 500 grams

T₁ = 25°C

T₂ = 75°C

specific heat of lead = 0.129 J/g°C

Energy required to heat the lead can be found by using the formula,

Q = (mass) (ΔT) (Cp)

Here, ΔT = T₂ - T₁ = 75 - 25 = 50

Substituting the values,

Q = (500)(50)(0.129)

Q = 3225 Joules.

Therefore, energy required is 3225 J.

3 0
2 years ago
Using only the following elements P, Br, and Mg, give the formulas for:A. an ionic compound. B. a molecular compound with polar
Talja [164]

Answer:

<h2>1. Ionic compound- MgBr_2</h2><h2>2. Polar molecular compound- PBr_3</h2>

Explanation:

Mg is a metal that has 12 atomic numbers and thus its electronic configuration is 1s^22s^22p^63s^2. The outer most shell of this element has 2 electrons so it loses 2 electrons and thus form Mg^2^+ ions. Br is a nonmetal and has 35 atomic number so its electronic configuration is 1s^22s^22p^63s^23p^64s^23d^1^04p^5. Since its outermost shell has 7 electrons so it can accept one electron and thus forms Br^-. So magnesium ion and bromide ion combine and forms an ionic compound MgBr_2.

P is also a nonmetal and combine with Br with covalent bond and due to electronegativity differences form polar covalent compound such as PBr_3.

8 0
1 year ago
A 250. ml sample of 0.0328m hcl is partially neutralized by the addition of 100. ml of 0.0245m naoh. find the concentration of h
Ksenya-84 [330]

Answer: 0.0164 molar concentration of hydrochloric acid in the resulting solution.

Explanation:

1) Molarity of 0.250 L HCl solution : 0.0328 M

Molarity=\frac{\text{Number of moles}}{\text{Volume of solution in liters}}=0.0328=\frac{\text{Number of moles}}{0.250 L}

Moles of HCl in 0.250 L solution = 0.0082 moles

2) Molarity of 0.100 L NaOH solution : 0.0245 M

Molarity=\frac{\text{Number of moles}}{\text{Volume of solution in liters}}=0.0245=\frac{\text{Number of moles}}{0.100 L}

Moles of NaOH in 0.100 L solution = 0.00245 moles

3) Concentration of hydrochloric acid in the resulting solution.

0.00245 moles of NaOH will neutralize 0.00245 moles of HCl out of 0.0082 moles of HCl.

Now the new volume of the solution = 0.100 L +0.250 L = 0.350 L

Moles of HCl left un-neutralized = 0.0082 moles - 0.00245 moles =  0.00575 moles

Molarity=\frac{\text{number of moles}}{\text{volume of solution in L}}

Molarity of HCl left un-neutralized :\frac{0.00575 moles}{0.350L}=0.0164 M

0.0164 molar concentration of hydrochloric acid in the resulting solution.

3 0
2 years ago
What is the osmotic pressure of a solution prepared from 13.7 g of the electrolyte HCl and enough water to make 0.500 L of solut
kherson [118]

Answer:

P = 17.9618 atm

Explanation:

The osmotic pressure can be calculated and treated as if we are talking about an ideal gas, and it's expression is the same:

pV = nRT

However the difference, is that instead of using moles, it use concentration so:

p = nRT/V ----> but M = n/V so

p = MRT

We have the temperature of 18 °C (K = 18+273.15 = 291.15 K) the value of R = 0.08206 L atm / K mol, so we need to calculate the concentration, and we have the mass of HCl, so we use the molar mass of HCl which is 36.45 g/mol:

n = 13.7/36.45 = 0.3759 moles

M = 0.3759/0.5 = 0.7518 M

Now that we have the concentration, let's solve for the osmotic pressure:

p = 0.7518 * 0.08206 * 291.15

<em><u>p = 17.9618 atm</u></em>

3 0
2 years ago
Which chemical activates the transformation of trypsinogen to trypsin?
jeka57 [31]
The answer should be <span>enteropeptidase

</span>
8 0
2 years ago
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