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2 years ago

Which contributes to the dissolution of sugar in water?

Chemistry

2 answers:

AURORKA [14]2 years ago

7 0

Option C: The dissociation of a polar covalent compound in water.

Sugar is made up of sucrose molecules containing polar covalent bonds. They have same type of oxygen-hydrogen covalent bonds that are present in water.

Since, sugar is not an ionic compound, option a and option b are incorrect. Also, due to same type of bonding in water and sugar molecules there will be no such force of attraction between them, this will opt out the option d.

Thus, dissolution of sugar in water is the dissociation of a polar covalent compound in water and option c is correct.

Veronika [31]2 years ago

3 0

I think the correct answer from the choices listed above is option d. It is the strong pull of water molecules on a polar covalent compound that contributes to the dissolution of sugar in water. Hope this answers the question.

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How much heat must be removed from 25.0g of steam at 118.0C in order to form ice at 15C

NemiM [27]

Answer:

-10778.95 J heat must be removed in order to form the ice at 15 °C.

Explanation:

Given data:

mass of steam = 25 g

Initial temperature = 118 °C

Final temperature = 15 °C

Heat released = ?

Solution:

Formula:

q = m . c . ΔT

we know that specific heat of water is 4.186 J/g.°C

ΔT = final temperature - initial temperature

ΔT = 15 °C - 118 °C

ΔT = -103 °C

now we will put the values in formula

q = m . c . ΔT

q = 25 g × 4.186 J/g.°C × -103 °C

q = -10778.95 J

so, -10778.95 J heat must be removed in order to form the ice at 15 °C.

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2 years ago

A certain electrochemical cell has for its cell reaction: zn + hgo → zno + hg which is the half-reaction occurring at the anode?

Leya [2.2K]

It is b because I'm just going around the house with me to the mall to get u at the moment I don't have any plans tonight or naw

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2 years ago

The combustion of 0.374 kg of methane in the presence of excess oxygen produces 0.983 kg of carbon dioxide. What is the percent

anyanavicka [17]

Assuming that the combustion formula is
CH4 + 2O2 --> 2H2O + CO2,

That means for every 1 molecule of methane(CH4) there will be one molecule of carbon dioxide(CO2) produced. Methane molecular weight 16, carbon dioxide molecular weight is 44. Then the percent yield should be:
1 * (0.374/ 16) /(0.983/44)= 0.374*44/ 0.983 * 16= 104.6%

You sure the number is correct? Percent yield should not exceed 100%

5 0

2 years ago

Respirometers were set up that contained yeast and 2% glucose solution. Each respirometer was placed at a different temperature.

Kitty [74]

Temperature is the independent variable in this experiment

Explanation:

A respirometer is a tool used to calculate the rate of breathing of a living organism by calculating the amount of exchange of oxygen and/or carbon dioxide.

When the yeast cells are given sugar in an aerobic (oxygen-containing) environment, then the yeast.

There would be an air bubble at the tip of the respirometer, and our dependent variable is the difference in the duration of the bubble, i.e. incubate in a warm water bath at body temperature (37 ° C) for about 20 minutes.

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2 years ago

Acetonitrile (CH3CN) is a polar organic solvent that dissolves a wide range of solutes, including many salts. The density of a 1

erastovalidia [21]

Answer:

a. [LiBr] = 2.70 m

b. Xm for LiBr = 0.1

c. 81% by mass CH₃CN

Explanation:

Solvent → Acetonitrile (CH₃CN)

Solute → LiBr, lithium bromide

We convert the moles of solute to mass → 1.80 mol . 86.84 g/1 mol = 156.3 g

This mass of solute is contained in 1L of solution

1 L = 1000 mL → 1mL = 1cm³

We determine solution mass by density

Solution density = Solution mass / Solution volume

Solution density . Solution volume = solution mass

0.824 g/cm³ . 1000 cm³ = 824 g

Mass of solution = 824 g (solvent + solute)

Mass of solute = 156.3 g

Mass of solvent = 824 g - 156.3 g = 667.7 g

Molality → Moles of solute in 1kg of solvent

We convert the mass of solvent from g to kg → 667.7 g . 1kg /1000g = 0.667 kg

Mol/kg → 1.80 mol / 0.667 kg = 2.70 m → molality

Mole fraction → Mole of solute / Total moles (moles solute + moles solvent)

Moles of solvent → 667.7 g . 1mol/ 41g = 16.3 moles

Total moles = 16.3 + 1.8 = 18.1

Mole fraction Li Br → 1.80 moles / 18.1 moles = 0.1

Mass percentage → (Mass of solvent, in this case / Total mass) . 100

We were asked for the acetonitrile → (667.7 g / 824 g) . 100 = 81%

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2 years ago