Answer:
<em>For both cases the answer is C</em>
Explanation:
We can see that the orbitals are not filled in the order of increasing energy and the Pauli exclusion principle is violated because it does not follow the correct order of the electron configuration; In the first exercise after the 2s2 orbital, the 2p2 orbital follows.
For the second exercise, you must start in order with level 1 and correctly filling each of the sublevels corresponding to each level until reaching level 7 and thus completing the desired number of electrons.
Explanation:
The given data is as follows.
![[P^{2-}]](https://tex.z-dn.net/?f=%5BP%5E%7B2-%7D%5D)
= 0.042 M, 
for 
According to the given situation 
acts as a base.The reaction equation will be as follows.
Relation between 
and are as follows.
= 
= 
Also, ![K_{b} = \frac{[HP^{-}][OH^{-}]}{P^{2-}}](https://tex.z-dn.net/?f=K_%7Bb%7D%20%3D%20%5Cfrac%7B%5BHP%5E%7B-%7D%5D%5BOH%5E%7B-%7D%5D%7D%7BP%5E%7B2-%7D%7D)
Let us take ![[OH^{-}] = [HP^{-}]](https://tex.z-dn.net/?f=%5BOH%5E%7B-%7D%5D%20%3D%20%5BHP%5E%7B-%7D%5D)
= x
So,
x = 
=
pOH = - log![[OH^{-}]](https://tex.z-dn.net/?f=%5BOH%5E%7B-%7D%5D)
= - log ()
= 4.99
As it is known that pH + pOH = 14
so, pH + 4.99 = 14
pH = 9.01
Thus, we can conclude that pH of the solution is 9.01.
Answer:
This question is incomplete
Explanation:
This question is incomplete but what you should know is that isopropanol (also referred to rubbing alcohol) has just one functional group. This functional group is called the hydroxyl group (-OH) and it's the reason the compound name ends with "ol". The hydroxyl group can be seen in the structure of the compound (Isopropanol) below
H OH H
| | |
H- C - C - C - H
| | |
H H H
If there is any functional group in isopropanol required for any form of interaction, that functional group will be the hydroxyl group because that's the only functional group isopropanol has.
NOTE: Functional group is an atom or group of atoms that determines the chemical properties of a compound.
Answer:
26.9 L SO₂
Explanation:
Step 1: Write the balanced equation
S(s) + O₂(g) = SO₂(g)
Step 2: Establish the appropriate volume ratio
For gases at the same conditions, the volume ratio is equal to the molar ratio. The volume ratio of O₂(g) to SO₂(g) is 1:1.
Step 3: Calculate the liters of SO₂ produced from 26.9 L of O₂
We will use the previously established volume ratio.
26.9 L O₂ × 1 L SO₂/1 L O₂ = 26.9 L SO₂
