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kati45 [8]
2 years ago
8

Carbon (C): 1sH2sI2pJ H = I = J =

Chemistry
2 answers:
ratelena [41]2 years ago
4 0

Answer:H=2 I=2 J=2

Explanation:

Greeley [361]2 years ago
4 0

Answer:

H= 2

I= 2

J=2

Explanation:

Just did this answer on ingenuity. :)

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Use the periodic table to identify the element indicated by each electron configuration by typing in the chemical symbol for the
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To determine what elements are represented by the electron configuration given above, we need to know the sum of the exponents of each term or subshell involved in the configuration as this represent the atomic number of the element.

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<span>1s2 2s2 2p6:                                      2 + 2 + 6 = 10                         neon
1s2 2s2 2p6 3s2 3p3:            </span>2 + 2 + 6 + 2 + 3 = <span>15                  phosphorus
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1s2 2s2 2p6 3s2 3p6 4s2 3d8:              20 + 8 =  28                    nickel
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3 0
1 year ago
Read 2 more answers
The French chemists, Pierre L. Dulong and Alexis T. Petit, noted in 1819 that the molar heat capacity of many solids at ordinary
natita [175]

The empirical formula of the compound : <u><em>RbO₂</em></u>

<h3>Further explanation</h3>

Dulong and Petit's rule's rule, which says that the molar heat capacity, Cp, of a solid can be expressed as

\large{\boxed{\bold{Cp=N(3R)}}

Where N is the number of atoms per formula unit and R is the universal gas constant

While the value of R is:

R = 8.3144621 J / K · mol

then:

3R = 24.94 J / K · mol

Heat capactiy per gram of a compound containing rubidium and oxygen is 0.64 J · K⁻¹ · g⁻¹

We try the possible empirical formula from the composition of Rb and O

  • Rb₂O

So the number of atoms: 3 (Rb = 2 atoms, O = 1 atom)

Then the value of the Cp:

Molar mass Rb₂O = 2.85.5 + 1.16 = 187 g/mol

\displaystyle Cp=N(3R)\\\\0.64=\frac{3.24.94}{187}\\\\0.64\neq0.4

Then this empirical formula Rb₂O  is not appropriate

  • RbO₂

So the number of atoms: 3 (Rb = 1 atom, O = 2 atoms)

Then the value of the Cp:

Molar mass RbO₂ = 1.85.5 + 2.16 = 117.5 g / mol

\displaystyle Cp=N(3R)\\\\0.64=\frac{3.24.94}{117.5}\\\\0.64=0.64

Then this empirical formula RbO₂  is appropriate

<h3>Learn more </h3>

chemical bond

brainly.com/question/5008811

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electron dots

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Keywords:  an empirical formula,compound, gas constant, Dulong and Petit's rule,the molar heat capacity

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7 0
2 years ago
A 0.15 m solution of chloroacetic acid has a ph of 1.86. What is the value of ka for this acid?
dem82 [27]

Answer: 1.67\times 10^{-3}

Explanation:

ClCH_2COOH\rightarrow ClCH_2COO^-+H^+

   cM              0             0

c-c\alpha        c\alpha          c\alpha  

So dissociation constant will be:

K_a=\frac{(c\alpha)^{2}}{c-c\alpha}

Given:  c = 0.15 M

pH = 1.86

K_a = ?

Putting in the values we get:

Also pH=-log[H^+]

1.86=-log[H^+]

[H^+]=0.01

[H^+]=c\times \alpha

0.01=0.15\times \alpha

\alpha=0.06

As [H^+]=[ClCH_2COO^-]=0.01

K_a=\frac{(0.01)^2}{(0.15-0.15\times 0.06)}

K_a=1.67\times 10^{-3]

Thus the vale of K_a for the acid is 1.67\times 10^{-3}

4 0
2 years ago
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I am sure the answer is A

7 0
2 years ago
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The atomic radius of magnesium is 150 pm. The atomic radius of strontium is 200 pm. What is the atomic radius of calcium
Anon25 [30]

Answer:

The atomic radius of calcium is approximately 175

Explanation:

Given that the atomic radius of magnesium = 150 pm

The atomic radius of strontium = 200 pm

Therefore, given that calcium comes in between magnesium and strontium in group 2 of the periodic table, the atomic radius should be half way between the length of the atomic radius of magnesium and strontium, given that the atomic radius is not a fixed quantity

Therefore;

The atomic radius of calcium is approximately given as follows;

The approximate atomic radius (200 + 150)/2 = 175 pm.

7 0
2 years ago
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