Answer:
Explanation:
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In this case, since this acid-base neutralization is performed in a 1:2 mole ratio of acid to base as the former is a diprotic acid (two hydrogen ions in the molecule), we can write the following equation:
In such a way, we can solve for the molarity of the acid, given the molarity and concentration of the NaOH base and the volume of the acid:
Thus, we plug in the given data to obtain:
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The NMR is attached that is required to answer this question. We are told that we have a carboxylic acid and that there is a nitro group directly attached to an aromatic ring. We can begin by determining the substitution on the aromatic ring.
Looking at the NMR spectrum, we a peak that integrates to 1 H at 12 ppm which is characteristic of a carboxylic acid, which we already know is present. Next we have two equivalent doublets that both integrate to 2 H, giving us 4 hydrogens in total. These doublets are in the aromatic region and this type of coupling pattern is characteristic of a 1,4-substituted aromatic ring, so we know there is only one other group substituted on the ring. However, the molecular formula is C₉H₉NO₄, so there are still 2 carbons not accounted for, if we include our carboxlic acid. Therefore, the carboxylic acid must be attached to some alkyl group which is substituted onto the aromatic ring.
We have a doublet at 1.6 ppm that integrates to 3, which suggests this is a methyl group adjacent to a CH. We also have a quartet at 4.0 ppm with an integration of 1. This suggests it is a CH that is adjacent to 3 hydrogen, most likely the methyl group we just described.
Therefore, we have a CH attached to a CH3, so that CH requires two more bonds. The only pieces left to attach to it are the aromatic ring and the carboxylic acid functional group. This gives us the structure shown in the image provided.
Given :
Rate = 75 m 1 s×60 s 1 min×1 h 60 m.
To Find :
Correct answer after conversion.
Solution :
We know, 1 min = 60 sec.
1 hour = 60 min = 60×60 sec = 3600 sec.
Putting value of min and hour in seconds , we get :
Hence, this is the required solution.
Each of the Isotopic mass * its Abundance Sum together divide by 100.
(179.946706*0.12 + 181.948206*26.5 + 182.9502245*14.3 + 183.9509326*30.64 + 185.954362*28.43 ) / 100
You get 183.84 (5s.f. ) or (183.8417786)
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<u>Answer:</u> The chemical equation is written below.
<u>Explanation:</u>
Combustion reaction is defined as the chemical reaction in which a hydrocarbon reacts with oxygen gas to produce carbon dioxide gas and water molecule.
The chemical equation for the combustion of ethyl chloride follows:
We are given:
When 4 moles of ethyl chloride is burnt, 5145 kJ of heat is released.
For an endothermic reaction, heat is getting absorbed during a chemical reaction and is written on the reactant side.
For an exothermic reaction, heat is getting released during a chemical reaction and is written on the product side
So, the chemical equation follows:
Hence, the chemical equation is written above.
