Answer:
223.08 K
Explanation:
First we <u>convert 173.0 °C to K</u>:
- 173.0 °C + 273.16 = 446.16 K
With the absolute temperature we can use <em>Charles' law</em> to solve this problem:
Where in this case:
We <u>input the data</u>:
- 446.16 K * 50 L = T₂ * 100 L
And <u>solve for T₂</u>:
Answer:
P = 17.9618 atm
Explanation:
The osmotic pressure can be calculated and treated as if we are talking about an ideal gas, and it's expression is the same:
pV = nRT
However the difference, is that instead of using moles, it use concentration so:
p = nRT/V ----> but M = n/V so
p = MRT
We have the temperature of 18 °C (K = 18+273.15 = 291.15 K) the value of R = 0.08206 L atm / K mol, so we need to calculate the concentration, and we have the mass of HCl, so we use the molar mass of HCl which is 36.45 g/mol:
n = 13.7/36.45 = 0.3759 moles
M = 0.3759/0.5 = 0.7518 M
Now that we have the concentration, let's solve for the osmotic pressure:
p = 0.7518 * 0.08206 * 291.15
<em><u>p = 17.9618 atm</u></em>
What's the answer? It asked to be 20 characters long so just writing this.
Answer:
Explanation:I would need more info to understand this question but explaining molecules is pretty easy tho
Concentration is the number of moles of solute in a fixed volume of solution
Concentration(c) = number of moles of solute(n) / volume of solution (v)
25.0 mL of water is added to 125 mL of a 0.150 M LiOH solution and solution becomes more diluted.
original solution molarity - 0.150 M
number of moles of LiOH in 1 L - 0.150 mol
number of LiOH moles in 0.125 L - 0.150 mol/ L x 0.125 L = 0.01875 mol
when 25.0 mL is added the number of moles of LiOH will remain constant but volume of the solution increases
new volume - 125 mL + 25 mL = 150 mL
therefore new molarity is
c = 0.01875 mol / 0.150 L = 0.125 M
answer is 0.125 M
