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UNO [17]
2 years ago
8

Which is the correct statement regarding the relative Rf values of the starting methyl benzoate vs the product, methyl m-nitrobe

nzoate on a silica gel TLC plate. The product has a higher Rf value on a silica gel TLC plate because it is less polar than the starting methyl benzoate. The product has a lower Rf value on a silica gel TLC plate because it is less polar than the starting methyl benzoate. The product has a higher Rf value on a silica gel TLC plate because it is more polar than the starting methyl benzoate. The product has a lower Rf value on a silica gel TLC plate because it is more polar than the starting methyl benzoate. 1.5 points QUESTION 2 Methyl benzoate is more reactive than benzene in Electrophilic Aromatic Substition [EAS] reactions. True False 1 points QUESTION 3 Methyl m-nitrobenzoate is less reactive than methyl benzoate in Electrophilic Aromatic Substition [EAS] reactions. True False
Chemistry
1 answer:
Marianna [84]2 years ago
5 0

Answer:

1. The product has a higher Rf value on a silica gel TLC plate because it is more polar than the starting methyl benzoate.

2. False

3. True

Explanation:

In chromatography, there is a stationary phase and a mobile phase. The ratio of the distance moved by a component and the distance moved by the solvent gives the retention factor (Rf).

Since silica gel is a polar solvent, it will retain the more polar product methyl m-nitrobenzoate compared to the methyl benzoate starting material.

In comparing the electrophillic aromatic substitution of m-nitrobenzoate  and methyl benzoate, we must remember that the presence of electron withdrawing groups (such as -NO2 and -CHO) on the aromatic compound deactivates the compound towards electrophillic aromatic substitution hence, methyl m-nitrobenzoate is less reactive than methyl benzoate in Electrophilic Aromatic Substition and Methyl benzoate is less reactive than benzene in Electrophilic Aromatic Substition

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Assume the following substances are soluble in water.
solmaris [256]

Ammonium carbonate will form 3 moles of ions.

Methyl alcohol will form 0 moles of ions.

Methane will form 0 moles of ions.

Aluminum sulfite will form 3 moles of ions.

Hydrobromic acid will form 2 moles of ions.

Explanation:

One mole of ammonium carbonate will form 3 moles of ions when dissolved in water.

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(actually it form ions because of its acidic behavior but they are at the order of 10⁻⁷ moles, however in the framework of this question we may say that there are none)

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Learn more about:

solvation of ions

brainly.com/question/5384053

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8 0
2 years ago
In Part B the given conditions were 1.00 mol of argon in a 0.500-L container at 27.0 ∘C . You identified that the ideal pressure
dimaraw [331]

Answer : The percent difference between the ideal and real gas is, 4.06 %.

Explanation : Given,

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The formula used to calculate percent difference is :

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Therefore, the percent difference between the ideal and real gas is, 4.06 %.

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MatroZZZ [7]

Answer:

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2 years ago
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