Question

What volume of 0.550 M KBr solution can you make from 100.0 mL of 2.50 M KBr?

Answer 1

M1V1 = M2V2
(2.50)(100.0) = (0.550)V2
V2 = 455mL

You can make 455mL of 0.550M solution from 100.0mL of 2.50M solution.

Answer 2

Answer : The volume of 0.550 M KBr solution you make from 100 ml of 2.50 M KBr is, 454.5 ml.

Solution :

According to the neutralization law,

$M_1V_1=M_2V_2$

where,

$M_1$ = molarity of KBr solution = 0.550 M

$V_1$ = volume of KBr solution = ?

$M_2$ = molarity of KBr = 2.50 M

$V_2$ = volume of KBr = 100 ml

Now put all the given values in the above law, we get the volume of KBr solution.

$(0.550M)\times V_1=(2.50M)\times (100ml)$

$V_1=454.5ml$

Therefore, the volume of 0.550 M KBr solution you make from 100 ml of 2.50 M KBr is, 454.5 ml.