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2 years ago

Draw a structure containing only carbon and hydrogen that is a stable alkyne of five carbons containing a ring.

Chemistry

1 answer:

stepladder [879]2 years ago

5 0

Answer:

Ethynylcyclopropane is the stable isomer for given alkyne.

Explanation:

In order to solve this problem we will first calculate the number of Hydrogen atoms. The general formula for alkynes is as,

CₙH₂ₙ₋₂

Putting value on n = 5,

C₅H₂.₅₋₂

C₅H₈

Also, the statement states that the compound contains one ring therefore, we will subtract 2 hydrogen atoms from the above formula i.e.

C₅H₈ ------------(-2 H) ----------> C₅H₆

Hence, the molecular formula for given compound is C₅H₆

Below, 4 different isomers with molecular formula C₅H₆ are attached.

The first compound i.e. ethynylcyclopropane is stable. As we know that alkynes are sp hybridized. The angle between C-C-H in alkynes is 180°. Hence, in this structure it can be seen that the alkyne part is linear and also the cyclopropane part is a well known moiety.

Compounds 3-ethylcycloprop-1-yne, cyclopentyne and 3-methylcyclobut-1-yne are highly unstable. The main reason for the instability is the presence of triple bond in three, five and four membered ring. As the alkynes are linear but the C-C-H bond in these compound is less than 180° which will make them highly unstable.

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A student sets up the following equation to convert a measurement. (The stands for a number the student is going to calculate.)

Aliun [14]

The question is incomplete, here is the complete question:

A student sets up the following equation to convert a measurement. (The stands for a number the student is going to calculate.) Fill in the missing part of this equation.

$23.Pa.cm^3=?kPa.m^3$

Answer: The measurement after converting is $23\times 10^{-9}kPa.m^3$

Explanation:

We are given:

A quantity having value $23.Pa.cm^3$

To convert this into $kPa.m^3$ , we need to use the conversion factors:

1 kPa = 1000 Pa

$1m^3=10^6cm^3$

Converting the quantity into $kPa.m^3$ , we get:

$\Rightarrow 23.Pa.cm^3\times (\frac{1kPa}{1000Pa})\times (\frac{1m^3}{10^6cm^3})\\\\\Rightarrow 23\times 10^{-9}kPa.m^3$

Hence, the measurement after converting is $23\times 10^{-9}kPa.m^3$

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2 years ago

The accepted value is 1.43. Which correctly describes this student’s experimental data?

Natalija [7]

Answer:

Neither accurate nor precise

Explanation:

The values were not near or even the same as the accepted value thus making it neither accurate nor precise.

4 0

2 years ago

Read 2 more answers

Interpret the following Arterial Blood Gases 1. pH 7.33 PaCO2 60 HCO3 34 A. Normal ABG values B. Respiratory acidosis without co

kicyunya [14]

Answer: 1) C; 2)D; 3)B; 4)B; 5) A

Explanation:Interpreting the following Arterial Blood gases, we have

1. pH 7.33 PaCO2 60 HCO3 34----Respiratory acidosis with partial compensation----C

2. pH 7.48 PaCO2 42 HCO3 30------. Metabolic alkalosis without compensation----D

3. pH 7.38 PaCO2 38 HCO3 24 ----- Normal---B

4. pH 7.21 PaCO2 60 HCO3 24------ Respiratory acidosis without compensation-----B

5. pH 7.48 PaCO2 28 HCO3 20 ----Respiratory alkalosis with partial compensation

The Arterial blood gas interpretation from analysis shows the pH and the partial pressures of oxygen and carbon dioxide in the arterial blood of an individual which can detect how well the lungs are functioning thereby making a physician make a diagnosis, estimate the severity of a condition and profer treatment.

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2 years ago

Ammonia gas is compressed from 21°C and 200 kPa to 1000 kPa in an adiabatic compressor with an efficiency of 0.82. Estimate the

Evgen [1.6K]

Explanation:

It is known that efficiency is denoted by $\eta$ .