Answer:
3.58 x 10^4 J
Explanation:
How many atoms of Mg are present in 97.22 grams of Mg?
1 answer:
Answer: Option (b) is the correct answer.
Explanation:
It is given that mass of Mg is 97.22 g and it is known that molar mass of Mg is 24.305 g/mol.
So, calculate the number of moles as follows.
No. of moles =
=
= 4 mol
Also, it is known that 1 mole has atoms/mol. Therefore, calculate the number of atoms in 4 mol as follows.
= atoms
or, = atoms
Thus, we can conclude that there are atoms in 97.22 grams of Mg.
You might be interested in
The Structure of Glycine is attached below and each central atom is encircled with different colors.
Molecular Shape around Nitrogen Atom (Orange):
As shown, Nitrogen is making three single bonds with two hydrogen atoms and one carbon atom hence, it has three bonded pair electrons and a single lone pair of electron. Therefore, according to VSEPR theory it has a tetrahedral electronic geometry but due to repulsion created by lone pair of electrons its molecular geometry becomes Trigonal Pyramidal.
Molecular Shape around Carbon Atom (Green):
As shown, Carbon is making four single bonds with two hydrogen atoms and one nitrogen atom one with carbon atom of carbonyl group hence, it has four bonded pair electrons. Therefore, according to VSEPR theory it has Tetrahedral geometry.
Molecular Shape around Carbon Atom (Blue):
As shown, Carbon is making two single bonds with oxygen and carbon atoms and a double bond with oxygen. Hence, it has a Trigonal Planar geometry.
Molecular Shape around Oxygen Atom (Red):
As shown, Oxygen is making two single bonds with one carbon atoms and one hydrogen atom hence, it has two bonded pair electrons and two lone pair of electrons. Therefore, according to VSEPR theory it has a tetrahedral electronic geometry but due to repulsion created by lone pair of electrons its molecular geometry becomes Bent.
