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olga2289 [7]
2 years ago
8

How many atoms of Mg are present in 97.22 grams of Mg?

Chemistry
1 answer:
Lostsunrise [7]2 years ago
7 0

Answer: Option (b) is the correct answer.

Explanation:

It is given that mass of Mg is 97.22 g and it is known that molar mass of Mg is 24.305 g/mol.

So, calculate the number of moles as follows.

          No. of moles = \frac{mass given in grams}{Molar mass}

                                 = \frac{97.22 g}{24.305 g/mol}  

                                 = 4 mol

Also, it is known that 1 mole has 6.023 \times 10^{23} atoms/mol. Therefore, calculate the number of atoms in 4 mol as follows.

               4 mol \times 6.023 \times 10^{23} atoms/mol

               = 24.08 \times 10^{23} atoms

or,            = 2.408 \times 10^{23} atoms

Thus, we can conclude that there are 2.408 \times 10^{23} atoms in 97.22 grams of Mg.

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A certain metal fluoride crystallizes in such a way that the fluoride ions occupy simple cubic lattice sites, while the metal io
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Answer:

MF_2

Explanation:

In a simple cubic lattice lattice, the atoms are present at the eight corners of the cibe.

Since it is mentioned that the fluorine is present at the corners and also 1 corners are shared by 8 unit cells. So, share of atom in one unit cell is:- 8\times \frac{1}{8}=1

Also, the metal, M occupy half of the body centre. A cube has only one body centre. So, share of M in each unit cell:- \frac{1}{2}

Thus, the formula is:-

M_{\frac{1}{2}}F Or simplifying MF_2

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2 years ago
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The snow gains heat to melt (endothermic), then the water releases heat to freeze (exothermic). ... Beaker becomes hot because the reaction is pushing heat out from itself onto .... solidification (ΔHsolidification) when 10.00kJ of energy are lost as 30.00g of water.

Explanation:

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How many moles of CO2 could fit in a 475 mL bag a -22° C and 855 mmHg?
Sergeeva-Olga [200]

Answer:

The amount of moles of CO₂ is 0.026 moles

Explanation:

An ideal gas is a theoretical gas that is considered to be composed of point particles that move randomly and do not interact with each other. Gases in general are ideal when they are at high temperatures and low pressures.

The equation known as the ideal gas equation explains the relationship between the four variables P (Pressure), V (Volume), T (Temperature) and n (Amount of substance). The ideal gas law is expressed mathematically as:

P*V = n*R*T

where P represents the pressure of the gas, V its volume, n the number of moles of gas (which must remain constant), R the constant of the gases and T the temperature of the gas.

In this case:

  • P= 855 mmHg
  • V= 475 mL= 0.475 L
  • n= ?
  • R= 62.36367 \frac{mmHg*L}{mol*K}
  • T= -22°C= 251 °K

Replacing:

855 mmHg*0.475 L=n*62.36367 \frac{mmHg*L}{mol*K} *251 °K

Solving:

n=\frac{855 mmHg*0.475 L}{62.36367 \frac{mmHg*L}{mol*K} *251 K}

n= 0.026 moles

<u><em>The amount of moles of CO₂ is 0.026 moles</em></u>

4 0
2 years ago
Suppose, in an experiment to determine the amount of sodium hypochlorite in bleach, you titrated a 26.34 mL sample of 0.0100 M K
Dmitry [639]

Answer:

0.1 M

Explanation:

The overall balanced reaction equation for the process is;

IO3^- (aq)+ 6H^+(aq) + 6S2O3^2-(aq) → I-(aq) + 3S4O6^2-(aq) + 3H2O(l)

Generally, we must note that;

1 mol of IO3^- require 6 moles of S2O3^2-

Thus;

n (iodate) = n(thiosulfate)/6

C(iodate) x V(iodate) = C(thiosulfate) x V(thiosulfate)/6

Concentration of iodate C(iodate)= 0.0100 M

Volume of iodate= V(iodate)= 26.34 ml

Concentration of thiosulphate= C(thiosulfate)= the unknown

Volume of thiosulphate=V(thiosulfate)= 15.51 ml

Hence;

C(iodate) x V(iodate) × 6/V(thiosulfate) = C(thiosulfate)

0.0100 M × 26.34 ml × 6/15.51 ml = 0.1 M

5 0
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