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wlad13 [49]
2 years ago
8

400 mL of hydrogen are collected over water at 18 C and a total pressure of 740 mm of mercury. (Vapor pressure of H2O at 18 C=15

.5mm).
a) What is the partial pressure of H2O?


b) What is the partial pressure of H2?
Chemistry
1 answer:
MrRa [10]2 years ago
6 0

Answer:

a)15.5 mmHg is the partial pressure of water vapor.

b) 724.5 mmHg is the partial pressure of hydrogen gas.

Explanation:

Total pressure of gases = T = P = 740 mmHg

Vapor pressure of the water = p_1=15.5 mmHg

Partial pressure of the hydrogen gas = p_2=?

Partial pressure of the water = p_1=15.5 mmHg

15.5 mmHg is the partial pressure of water vapor.

Using Dalton's law of partial pressure:

P=p_1+p_2

740 mmHg=15.5 mmHg+p_2

p_2=740 mmHg-15.5mmHg =724.5 mmHg

724.5 mmHg is the partial pressure of hydrogen gas.

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AVprozaik [17]

Answer:

E° = 0.65 V

Explanation:

Let's consider the following reductions and their respective standard reduction potentials.

Sn⁴⁺(aq) + 2 e⁻ → Sn²⁺(aq) E°red = 0.15 V

Ag⁺(aq) + e⁻ → Ag(s) E°red = 0.80 V

The reaction with the highest reduction potential will occur as a reduction while the other will occur as an oxidation. The corresponding half-reactions are:

Reduction (cathode): Ag⁺(aq) + e⁻ → Ag(s) E°red = 0.80 V

Oxidation (anode): Sn²⁺(aq) → Sn⁴⁺(aq) + 2 e⁻ E°red = 0.15 V

The overall cell potential (E°) is the difference between the standard reduction potential of the cathode and the standard reduction potential of the anode.

E° = E°red, cat - E°red, an = 0.80 V - 0.15 V = 0.65 V

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2 years ago
Jeff wants to find the volume of a gas in a cylinder. He knows that at 28°C and a pressure of 1 atm, the volume of the gas was 6
emmasim [6.3K]

Answer:

by using ideal gas law

Explanation:

ideal gas law:

PV=nRT

where:

P is pressure measured in Pascal (pa)

V is volume measured in letters (L)

n is number of moles

R is ideal gas constant

T is temperature measured in Kelvin (K)

by applying the given:

P(initial) V(initial)=nRT(initial)

P(final) V(final)=nRT(final)

nR is constant in both equations since same gas

then,

P(initial) V(initial) / T(initial) = P(final) V(final) / T(final)

then by crossing multiply both equations

V (final)= { (P(initial) V(initial) / T(initial)) T(final) } /P (final)

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V(initial)= 6 L

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T(final) = 39°c = 39+273 kelvin

by substitution

V(final) = 6.21926 L

6 0
1 year ago
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umka21 [38]

Answer:

Explanation:

find the solution below

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2 years ago
What is the ph of a solution that consists of 0.50 m h2c6h6o6 (ascorbic acid) and 0.75 m nahc6h6o6 (sodium ascorbate)? ka = 6.8
bearhunter [10]

Answer:

4.34.

Explanation:

  • For acidic buffer:

<em>∵ pH = pKa + log [salt]/[Acid]</em>

∴ pH = - log(Ka) + log [salt]/[Acid]

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4 0
2 years ago
What is the empirical formula of a compound containing 5.03 grams carbon, 0.42 grams hydrogen, and 44.5 grams chlorine?
Thepotemich [5.8K]

Answer:

CHCl₃

Explanation:

Given parameters:

Carbon = 5.03g

Hydrogen = 0.42g

Chlorine = 44.5g

The empirical formula shows the simplest formula of a compound.

To deduce the empirical, we need two pieces of information:

> Mass of the elements or the percentage composition of the compound

>The relative atomic masses of the elements

In order to derive the empirical formula from these parameters,

>>> find the number of moles of elements by dividing the mass given by the relative atomic mass of the respective atom

>>> Divide through by the smallest mole

>>> Approximate or multiply by a factor that would make it possible for whole numbers to be obtained

From the question, we have been given the mass of each element.

Now using the period table, we can obtain the relative atomic masses of each atom:

Carbon = 12gmol⁻¹

Hydrogen = 1gmol⁻¹

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C H Cl

Mass(in g) 5.03 0.42 44.5

Moles 5.03/12 0.42/1 44.5/37.5

0.42 0.42 1.19

Dividing

by

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Mole ratio 1 1 2.83

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The empirical formula is CHCl₃

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2 years ago
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