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pickupchik [31]
2 years ago
12

Elemental analysis of the unknown gas from part a revealed that it is 30.45% n and 69.55% o. what is the molecular formula for t

his gas? express your answer as a chemical formula.
Chemistry
1 answer:
Gnesinka [82]2 years ago
6 0

Assuming we have 100 g of sample

30.45/MW of N 14g = 2.175

69.55/MW of O 16g = 4.34

4.34/2.185 = 2

for every 1 mole of N we have 2 moles of O

so the empirical formula would be NO2

without having the molecular weight of the entire molecule the molecular formula can not be determined with the information in your question

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a compound is found to have 46.67% nitrogen, 6.70% hydrogen, 19.98% carbon and 26.65% oxygen, what is the empirical formula?
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Search up “Chemistry, how to do empirical formulas” a guy named Tyler Dewitt is really good at explaining
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2 years ago
Explain why neither the oil nor the glass fiber interferes with the diffraction pattern of the crystal.
SVEN [57.7K]
<span>It's because The oil and the glass fibers do not interfere with X-ray crystallographic measurements because only one is crystalline.
</span><span>Glass fibers have a low absorbance for </span>X-rays<span> and is </span><span>not crystalline. Because of this, glass fibers will not interfere with X-Ray patterns. Oil, on the other hand, could be considered as crytalline.</span>
8 0
2 years ago
A. The measured pH of a 0.100 M HCl solution at 25 degrees Celsius is 1.092. From this information, calculate the activity coeff
ra1l [238]

Answer:

activity coefficient \mathbf{\gamma =0.809}

activity coefficient \mathbf{\gamma = 0.791}

The change in pH in part A = 0.092

The change in pH in part B =  0.102

Explanation:

From the given information:

pH of HCl solution = 1.092

Activity of the pH solution [a] = 10^{-1.092}

[a] = 0.0809 M

Recall that [a] = \gamma × C

where;

\gamma  = activity coefficient

C = concentration

Making the activity coefficient the subject of the formula, we have:

\gamma = \dfrac{[a]}{C}

\gamma = \dfrac{0.0809 \ M}{0.100  \ M}

\mathbf{\gamma =0.809}

B.

The pH of a solution of HCl and KCl = 2.102

[a] = 10^{-2.102}

[a] = 0.00791 M

activity coefficient \gamma = \dfrac{0.00791 \ M}{0.01 \ M}

\mathbf{\gamma = 0.791}

C. The change in pH in part A = 1.091 - 1.0 = 0.092

The change in pH in part B = 2.102 -2.00 = 0.102

3 0
2 years ago
Find the number of moles of water that can be formed if you have 170 mol of hydrogen gas and 80 mol of oxygen gas. Express your
Sav [38]

<u>Answer:</u> The amount of water that can be formed is 160 moles

<u>Explanation:</u>

We are given:

Moles of hydrogen gas = 170 moles

Moles of oxygen gas = 80 moles

The chemical equation for the reaction of hydrogen gas and oxygen gas follows:

2H_2+O_2\rightarrow 2H_2O

By Stoichiometry of the reaction:

1 mole of oxygen gas reacts with 2 moles of hydrogen gas

So, 80 moles of oxygen gas will react with = \frac{2}{1}\times 80=160mol of hydrogen gas

As, given amount of hydrogen gas is more than the required amount. So, it is considered as an excess reagent.

Thus, oxygen gas is considered as a limiting reagent because it limits the formation of product.

By Stoichiometry of the reaction:

1 mole of oxygen gas produces 2 moles of water

So, 80 moles of oxygen gas will produce = \frac{2}{1}\times 80=160moles of water

Hence, the amount of water that can be formed is 160 moles

3 0
2 years ago
Write equation for the first ionization energy of neon. express your answer as a chemical equation. identify all of the phases i
Montano1993 [528]

The first ionization energy of a known element is the energy it needs to remove its highest energy or outermost electron. It is done to make a neutral atom be a positively charged ion. The first ionization energy of neon as a chemical equation is this:

Ne (g) -> Ne+ (g) + e-

 

8 0
2 years ago
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