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bekas [8.4K]
2 years ago
13

Identify the precipitate (if any) that forms when nach3coo (also written as nac2h3o2) and hcl are mixed. express your answer as

a chemical formula. enter noreaction if no precipitate is formed.
Chemistry
2 answers:
Karolina [17]2 years ago
3 0
When NaCH3Coo mixed with HCl we will get NaCl and CH3CooH as shown in the following balanced equation:

NaCH3Coo + HCl → NaCl + CH3CooH
so from this equation, we can conclude that is no precipitate because all we get is the acetic acid which found in vinegar and the NaCl which is very soluble so we don't have any precipitate.
so, your answer is no precipitate, no reaction
sasho [114]2 years ago
3 0

There is no precipitate formed when {\mathbf{NaC}}{{\mathbf{H}}_{\mathbf{3}}}{\mathbf{COO}} is mixed with HCl.

Further Explanation:

Precipitation reactions:

The formation of insoluble saltby chemical combination of two solutions of soluble salts is called precipitation reaction.The insoluble salt formed during such reactions is called precipitate. Due to formation of precipitates, these reactions are known as precipitation reactions. These reactions are used in determining the presence of different ions existing in particular solutions.

{\text{NaC}}{{\text{H}}_{\text{3}}}{\text{COO}} is the sodium salt of acetic acid. HCl is strong acid so it has the ability to displace sodium from its salt. Therefore when solutions of {\text{NaC}}{{\text{H}}_{\text{3}}}{\text{COO}} and HCl are mixed, it leads to the formation of sodium chloride and acetic acid. Both these products are water-soluble. But precipitate is insoluble salt that is highly insoluble in water and separates as solid.

The chemical reaction between {\text{NaC}}{{\text{H}}_{\text{3}}}{\text{COO}} and HCl occurs as follows:

{\text{NaC}}{{\text{H}}_{\text{3}}}{\text{COO}} + {\text{HCl}} \to {\text{NaCl}} + {\text{C}}{{\text{H}}_{\text{3}}}{\text{COOH}}  

Since this reaction does not involve formation of any insoluble salt, no precipitation occurs during this reaction. Hence no precipitates are formed when solutions of {\text{NaC}}{{\text{H}}_{\text{3}}}{\text{COO}} and HCl are mixed.

Learn more:

  1. Balanced chemical equation: brainly.com/question/1405182
  2. Oxidation and reduction reaction: brainly.com/question/2973661

Answer details:

Grade: Senior School

Subject: Chemistry

Chapter: Chemical reactions and equations  

Keywords: NaCH3COO, HCl, CH3COOH, NaCl, precipitate, soluble salts, insoluble salts, no precipitate, salt, displace, solid, highly insoluble, precipitation reaction.

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3. According to the label on a bottle of concentrated hydrochloric acid, the contents are 36.0% HCl by mass and have a density o
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a) 11.64 M

b) 43 mL

c) 1.7 kg

Explanation:

a) Let's use a basis of the calculus of 1000 mL (1 L) of the concentrated solution. If the solution has 1.18 g/mL, it has:

1.18*1000 = 1180 g.

The mass of HCl will be then:

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c) The neutralization will happen by the equation:

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The solubility of KCl is 3.7 M at 20 °C. Two beakers each contain 100. mL of saturated KCl solution: 100. mL of 4.0 M HCl is add
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Answer:

a)The Ksp was found to be equal to 13.69

Explanation:

Terminology

Qsp of a dissolving ionic solid — is the solubility product of the concentration of ions in solution.

Ksp however, is the solubility product of the concentration of ions in solution at EQUILIBRIUM with the dissolving ionic solid.

Note that if Qsp > Ksp , the solid at a certain temperature, will precipitate and form solid. That means the equilibrium will shift to the left in order to attain or reach equilibrium (Ksp).

Step-by-step solution:

To solve this: 

#./ Substitute the molar solubility of KCl as given into the ion-product equation to find the Ksp of KCl.

#./ Find the total concentration of ionic chloride in each beaker after the addition of HCl. We pay attention to the amount moles present at the beginning and the moles added.

#./ Find the Qsp value to to know if Ksp is exceeded. If Qsp < Ksp, nothing will precipitate.

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In pure water KCl

Ksp =13.69 KCl =[K+][Cl-]

Let x= molar solubility [K+],/[Cl-] :. × , x

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The Ksp was found to be equal to 14.

4.0 M HCl = KCl =[K+][Cl-]

Let y= molar solubility :. y, y+4

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* - rule of thumb

Ksp =13.69= [K+][Cl-] = (y)(y*+4)= y(4)

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8 M HCl = KCl =[K+][Cl-]

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Ksp =13.69= [K+][Cl-] = (b)(b*+8)= b(8)

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