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bekas [8.4K]
2 years ago
13

Identify the precipitate (if any) that forms when nach3coo (also written as nac2h3o2) and hcl are mixed. express your answer as

a chemical formula. enter noreaction if no precipitate is formed.
Chemistry
2 answers:
Karolina [17]2 years ago
3 0
When NaCH3Coo mixed with HCl we will get NaCl and CH3CooH as shown in the following balanced equation:

NaCH3Coo + HCl → NaCl + CH3CooH
so from this equation, we can conclude that is no precipitate because all we get is the acetic acid which found in vinegar and the NaCl which is very soluble so we don't have any precipitate.
so, your answer is no precipitate, no reaction
sasho [114]2 years ago
3 0

There is no precipitate formed when {\mathbf{NaC}}{{\mathbf{H}}_{\mathbf{3}}}{\mathbf{COO}} is mixed with HCl.

Further Explanation:

Precipitation reactions:

The formation of insoluble saltby chemical combination of two solutions of soluble salts is called precipitation reaction.The insoluble salt formed during such reactions is called precipitate. Due to formation of precipitates, these reactions are known as precipitation reactions. These reactions are used in determining the presence of different ions existing in particular solutions.

{\text{NaC}}{{\text{H}}_{\text{3}}}{\text{COO}} is the sodium salt of acetic acid. HCl is strong acid so it has the ability to displace sodium from its salt. Therefore when solutions of {\text{NaC}}{{\text{H}}_{\text{3}}}{\text{COO}} and HCl are mixed, it leads to the formation of sodium chloride and acetic acid. Both these products are water-soluble. But precipitate is insoluble salt that is highly insoluble in water and separates as solid.

The chemical reaction between {\text{NaC}}{{\text{H}}_{\text{3}}}{\text{COO}} and HCl occurs as follows:

{\text{NaC}}{{\text{H}}_{\text{3}}}{\text{COO}} + {\text{HCl}} \to {\text{NaCl}} + {\text{C}}{{\text{H}}_{\text{3}}}{\text{COOH}}  

Since this reaction does not involve formation of any insoluble salt, no precipitation occurs during this reaction. Hence no precipitates are formed when solutions of {\text{NaC}}{{\text{H}}_{\text{3}}}{\text{COO}} and HCl are mixed.

Learn more:

  1. Balanced chemical equation: brainly.com/question/1405182
  2. Oxidation and reduction reaction: brainly.com/question/2973661

Answer details:

Grade: Senior School

Subject: Chemistry

Chapter: Chemical reactions and equations  

Keywords: NaCH3COO, HCl, CH3COOH, NaCl, precipitate, soluble salts, insoluble salts, no precipitate, salt, displace, solid, highly insoluble, precipitation reaction.

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Answer:

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Explanation:

Taking The molecular weight of NaCl = 58.44 grams/mole

<u>Determine how many grams of NaCl to prepare the bath solution </u>

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next

determine how many grams of NaCl

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4 0
2 years ago
Calculate the number of atoms in 2.5 mol manganese.
Leokris [45]

Answer:

1.5 × 10²⁴ atoms Mn

General Formulas and Concepts:

<u>Chemistry - Atomic Structure</u>

  • Reading a Periodic Table
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Explanation:

<u>Step 1: Define</u>

2.5 mol Mn

<u>Step 2: Identify Conversions</u>

Avogadro's Number

<u>Step 3: Convert</u>

<u />2.5 \ mol \ Mn(\frac{6.022 \cdot 10^{23} \ atoms \ Mn}{1 \ mol \ Mn} ) = 1.5055 × 10²⁴ atoms Mn

<u>Step 4: Check</u>

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6 0
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Answer:

Mass_{chromium}=52.1\ g

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Explanation:

<u>Calculation of the mass of chromium as:- </u>

Moles = 1.002 moles

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The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

1.002\ mol= \frac{Mass}{51.9961\ g/mol}

Mass_{chromium}=1.002\times 51.9961\ g = 52.1\ g

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Moles = 4.08\times 10^{-8} moles

Molar mass of neon = 20.1797 g/mol

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1.002\ mol= \frac{Mass}{20.1797\ g/mol}

Mass_{neon}=4.08\times 10^{-8}\times 20.1797\ g = 8.23\times 10^{-7}\ g

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