Calculate the molarity of a solution that contains 70.0 g of H2SO4 in 280. mL of solution.
1 answer:
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Answer:
4 moles of and 1 mole of
will be present in the reaction vessel
Explanation:
The reaction given in the question is
⇒
According to the stoichiometric coefficients of the reaction, 2 moles of requires 3 moles of
so in this reaction,
is a limiting reagent. So we will consider that
is in excess.
Now,
Since 3 moles of requires 2 moles of
So, for 6 moles of the moles of
required =
= 4 moles.
Moles of remaining after the completion of reaction = 5 - 4 = 1 mole.
Again,
Since 3 moles of produces 2 moles of
So, moles of produced by 6 moles of
=
= 4 moles.
Therefore, after the completion of reaction, 4 moles of and 1 mole of
will be present in the reaction vessel.