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1 year ago

Calculate the molarity of a solution that contains 70.0 g of H2SO4 in 280. mL of solution.

1 answer:

8 0

First convert grams to moles:
70.0g *(mole/98.079) = 0.7137mole
Remember that molarity is moles per liter:
0.7137mole *(1/280mL) *(1000mL/L) = 25.5M

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A) How many moles of CO2 and H2O are formed from 3.85 mole of propane C3H8 (This calculation needs to be done twice-once fro CO2

4vir4ik [10]

Answer:

a) 11.55 moles of carbon dioxide gas are formed from 3.85 mole of propane.

15.4 moles of water are formed from 3.85 mole of propane.

b)0.5176 moles of water are formed from 0.647 mole of oxygen gas.

0.1294 moles of propane are consumed.

Explanation:

$C_3H_7+5O_2\rightarrow 3CO_2+4H_2O$

a) Moles of propane = 3.85 moles

According to reaction, 1 mole of propane gives 3 moles of carbon dioxide gas.

Then 3.85 moles of propane will give:

$\frac{3}{1}\times 3.85 mol=11.55 mol$ of carbon dioxide gas.

11.55 moles of carbon dioxide gas are formed from 3.85 mole of propane.

According to reaction, 1 mole of propane gives 4 moles of water gas.

Then 3.85 moles of propane will give:

$\frac{4}{1}\times 3.85 mol=15.4 mol$ of water .

15.4 moles of water are formed from 3.85 mole of propane.

b) Moles of oxygen gas = 0.647 moles

According to reaction, 5 mole of oxygen gas gives 4 moles of water.

Then 0.647 moles of oxygen will give:

$\frac{4}{5}\times 0.647 mol=0.5176 mol$ of water.

0.5176 moles of water are formed from 0.647 mole of oxygen gas.

According to reaction, 5 mole of oxygen gas reacts with 1 mole of propane.

Then 0.647 moles of oxygen will give:

$\frac{1}{5}\times 0.647 mol=0.1294 mol$ of propane.

0.1294 moles of propane are consumed.

5 0

2 years ago

A crystal of graphite contains which type of bond?

cupoosta [38]

Answer:Graphite has a giant covalent structure in which: each carbon atom is joined to three other carbon atoms by covalent bonds.

4 0

1 year ago

Read 2 more answers

How many miles of Fe2+ ions and MnO4- ions were titrated in each part 1 trial

Fudgin [204]

Answer:

In 1000 ml there is 0.10 moles of Fe 2+

Therefore, in 10 ml there is (0.1/1000)*10= 0.001 mol of Fe2+

mole ratio for rxn Fe2+ : MnO4- is

1 : 2

therefore if 0.001 moles of Fe2+ react then 0.001*2 =0.002 moles of MnO4- react with Fe2+

hence, molarity of MnO4- = (mol*vol)/1000

= 0.002*10.75/1000= 2.15*10-5M

Explanation:

Hope this helps

5 0

2 years ago

A voltaic cell is constructed with two silver-silver chloride electrodes, where the half-reaction is AgCl (s) + e− → Ag (s) + Cl

ANTONII [103]

Answer : The cell emf for this cell is 0.118 V

Solution :

The half-cell reaction is:

$AgCl(s)+e^\rightarrow Ag(s)+Cl^-(aq)$

In this case, the cathode and anode both are same. So, $E^o_{cell}$ is equal to zero.

Now we have to calculate the cell emf.

Using Nernest equation :

$E_{cell}=E^o_{cell}-\frac{0.0592}{n}\log \frac{[Cl^{-}{diluted}]}{[Cl^{-}{concentrated}]}$

where,

n = number of electrons in oxidation-reduction reaction = 1

$E_{cell}$ = ?

$[Cl^{-}{diluted}]$ = 0.0222 M

$[Cl^{-}{concentrated}]$ = 2.22 M

Now put all the given values in the above equation, we get:

$E_{cell}=0-\frac{0.0592}{1}\log \frac{0.0222M}{2.22M}$

$E_{cell}=0.118V$

Therefore, the cell emf for this cell is 0.118 V

4 0

2 years ago

The lewis structure of n2h2 shows __________.

Ghella [55]

The Lewis structure of Diimide (N₂H₂) is shown below.

In this molecule two Nitrogen atoms attached to each other through a double bond are further attached to one one Hydrogen atom. Also, each Nitrogen atom carries one non-binding electron pair (Lone Pair) (Highlighted RED).

Result:
Option-C (<span>each nitrogen has one nonbinding electron pair) is the correct answer.</span>

5 0

2 years ago

Read 2 more answers