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erastova [34]
1 year ago
5

Calcite is mineral that is found in limestone and marble. A model of the extended structure of calcite is

Chemistry
1 answer:
icang [17]1 year ago
7 0

Answer:

B. It is formed by a repeating pattern of a single type of atom

Explanation:

i think thats answer may i get brainlest?

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According to the bohr model of the atom, the single electron in what motion of a hydrogen atom circles the nucleus
Lady bird [3.3K]
It would be elliptical according to him.....
4 0
1 year ago
The first ionization energy, e, of a potassium atom is 0.696 aj. what is the wavelength of light, in nm, that is just sufficient
elena55 [62]
The formula to be used for this problem is as follows:

E = hc/λ, where h is the Planck's constant, c is the speed of light and λ is the wavelength. Also 1 aJ = 10⁻¹⁸ J

0.696×10⁻¹⁸ = (6.62607004×10⁻³⁴ m²·kg/s)(3×10⁸ m/s)/λ
Solving for λ,
λ = 2.656×10⁻⁷ m or <em>0.022656 nm</em>
6 0
1 year ago
En una determinación cuantitativa se utilizan 17.1 mL de Na2S2O3 0.1N para que reaccione todo el yodo que se encuentra en una mu
lozanna [386]

Answer:

La cantidad de yodo en la muestra es 0.217 g

Explanation:

Los parámetros dados son;

Normalidad de la solución de Na₂S₂O₃ = 0.1 N

Volumen de la solución de Na₂S₂O₃ = 17.1 mL

Masa de muestra = 0.376 g

La ecuación de reacción química se da de la siguiente manera;

I₂ + 2Na₂S₂O₃ → 2 · NaI + Na₂S₄O₆

Por lo tanto, el número de moles de sodio por 1 mol de Na₂S₂O₃ en la reacción = 1 mol

Por lo tanto, la normalidad por mol = 1 M × 1 átomo de Na = 1 N

Por lo tanto, 0.1 N = 0.1 M

El número de moles de Na₂S₂O₃ en 17,1 ml de solución 0,1 M de Na₂S₂O₃ se da de la siguiente manera;

Número de moles de Na₂S₂O₃ = 17.1 / 1000 × 0.1 = 0.00171 moles

Lo que da;

Un mol de yodo, I₂, reacciona con dos moles de Na₂S₂O₃

Por lo tanto;

0,000855 moles de yodo, I₂, reaccionan con 0,00171 moles de Na₂S₂O₃

La masa molar de yodo = 253.8089 g / mol

La masa de yodo en la muestra = 253.8089 × 0.000855 = 0.217 g.

5 0
2 years ago
The solubility of acetanilide in hot water (5.5 g/100 ml at 100 C) is not very great, and it has some solubility in cold water (
sashaice [31]

To answer the problem given:

|0.53−4.0| / 4.0 * 100%

= 3.47 / 4.0 * 100%

= 87%

The maximum theoretical percent recovery from the crystallization of 4.0 g of acetanilide from 100 ml of water is 87%. I am hoping that this answer has satisfied your query and it will be able to help you in your endeavor, and if you would like, feel free to ask another question.

5 0
2 years ago
Read 2 more answers
You are asked to go into the lab and prepare an acetic acid - sodium acetate buffer solution with a ph of 4.00  0.02. what mola
Oxana [17]
Hello!

To solve this problem we are going to use the Henderson-Hasselbach equation and clear for the molar ratio. Keep in mind that we need the value for Acetic Acid's pKa, which can be found in tables and is 4,76:

 pH=pKa + log ( \frac{[CH_3COONa]}{[CH_3COOH]} )

\frac{[CH_3COOH]}{[CH_3COONa}= 10^{(pH-pKa)^{-1}}=10^{(4-4,76)^{-1}}=5,75

So, the mole ratio of CH₃COOH to CH₃COONa is 5,75

Have a nice day!

5 0
2 years ago
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