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GaryK [48]
1 year ago
5

As illustrated, the below manometer consists of a gas vessel and an open-ended U-tube containing a nonvolatile liquid with a den

sity of 0.993 g/mL. The difference in heights of the liquid in the two sides of the manometer is 32.3mm when the atmospheric pressure is 765 mm Hg. Given that the density of mercury is 13.6 g/mL, the pressure of the enclosed gas is ________ atm. Group of answer choices
Chemistry
1 answer:
STALIN [3.7K]1 year ago
5 0

Answer:

1.01atm is the pressure of the gas

Explanation:

The difference in heights in the two sides is because of the difference in  pressure of the enclosed gas and the atmospheric pressure. This difference is in mm of the nonvolatile liquid. The difference in mm Hg is:

32.3mm * (0.993g/mL / 13.6g/mL) = 2.36mmHg

As atmospheric pressure is 765mm Hg and assuming the gas has more pressure than the atmospheric pressure (There is no illustration), the pressure of the gas is:

765mm Hg + 2.36mm Hg = 767.36 mmHg

In atm:

767.36 mmHg * (1atm / 760 mmHg) =

1.01atm is the pressure of the gas

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3 0
2 years ago
3. A mass of 0.15 ounces is equal to how many grams?
garik1379 [7]

Answer:

Option C = 4.25 g

Explanation:

Ounce and grams are unit of mass. Ounce is larger unit while gram is smaller unit. The one ounce is consist of 28.35 g or we can say that one ounce is equal to 28.35 g. In order to convert the given ounce value into grams the value is multiply with 28.35 g.

Given data:

Mass = 0.15 ounce

Mass in gram = ?

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One ounce is equal to 28.35 g, so

0.15 × 28.35 = 4.25 g

5 0
2 years ago
Magnesium and nitrogen react in a combination reaction to produce magnesium nitride: 3 Mg N2 → Mg3N2 In a particular experiment,
vlada-n [284]

Answer:

The mass of Mg consumed is 21.42g

Explanation:

The reaction is

3Mg+N_{2}-->Mg_{3}N_{2}

As per balanced equation, three moles of Mg will react with one mole of nitrogen to give one mole of magnesium nitride.

as given that mass of nitrogen reacted = 8.33g

So moles of nitrogen reacted = \frac{mass}{molarmass}=\frac{8.33}{28}=0.2975mol

moles of Mg required = 3 X moles of nitrogen taken = 3X0.2975 = 0.8925mol

Mass of Mg required = moles X molar mass = 0.8925 X 24 = 21.42 g

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2 years ago
The mass unit associated with density is usually grams. if the volume (in ml or cm3) is multiplied by the density (g/ml or g/cm3
jok3333 [9.3K]

The weight in grams = 7.93 g

Given volume = 2.00 in^{3}

Given  density = 0.242 g/cm^{3}

We need to find the Mass(weight) in grams.

To find the weight in grams we need to keep in mind that the volume and density must use the same volume unit for cancellation. So that the volume units will cancel out, leaving only the mass units.

The unit of given volume is in^{3} and unit of volume in density is cm^{3} , so first we need to change the unit of volume from in^{3} to cm^{3} so that the volume units will cancel out, leaving only the mass units.

1 in^{3} = 16.39 cm^{3} (given conversion)

2 in^{3}\times \frac{(16.39 cm^{3})}{(1 in^{3})}

in^{3} units get cancel out leaving the cm^{3} unit.

2 in^{3} = 32.78 cm^{3}

Mass = Density X Volume.

Density = 0.242 g/cm^{3} and Volume = 32.78 cm^{3}

Mass =0.242\frac{g}{cm^{3}}\times 32.78 cm^{3}

Mass = 7.93 grams (g)


3 0
1 year ago
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