Answer : The value of is, 11.2
The value of is -9.04 kJ/mol
Explanation :
The relation between the equilibrium constant and standard Gibbs free energy is:
where,
= standard Gibbs free energy = -5.980 kJ/mol = -5980 J/mol
R = gas constant = 8.314 J/K.mol
T = temperature =
= equilibrium constant = ?
Now put all the given values in the above formula, we get:
Thus, the value of is, 11.2
Now we have to calculate the .
The formula used for is:
The given reaction is:
............(1)
where,
= Gibbs free energy for the reaction = ?
= standard Gibbs free energy = -30.5 kJ/mol
R = gas constant =
T = temperature =
Q = reaction quotient
[A] = concentration of A = 1.8 M
[B] = concentration of B = 0.55 M
Now put all the given values in the above formula 1, we get:
Therefore, the value of is -9.04 kJ/mol
