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Digiron [165]
1 year ago
13

A beach has a supply of sand grains composed of calcite, ferromagnesian silicate minerals, and non-ferromagnesian silicate miner

als. If it undergoes lots of chemical weathering, which sand grains will be quickly chemically weathered away?
a. Calcite
b. ferromagnesian silicate minerals
c. non-ferromagnesian silicate minerals
Chemistry
1 answer:
bezimeni [28]1 year ago
4 0
Ferromagnesian silicate minerals (i looked it up)
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(S)-5,5-dibromo-3-fluoro-2-methyl-3-hexanol
blsea [12.9K]
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What happens when Ammonia reacts with zinc sulphate solution
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It will form a tetraamminezinc sulphate and a blue solution will be formed...the reaction should be carried out in a fume chamber because a poisonous substance will be released to the atmosphere
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2 years ago
How much energy is transferred when 30.0<br> g of water is cooled from 25.0 °C to 12.7 °C.
enot [183]

Answer:

Heat transferred, Q = 1542.42 J

Explanation:

Given that,

Mass of water, m = 30 grams

Initial temperature, T_i=25^{\circ} C

Final temperature, T_f=12.7^{\circ} C

We need to find the energy transferred. The energy transferred is given by :

Q=mc\Delta T

c is specific heat of water, c = 4.18 J/g °C

So,

Q=30\ g\times 4.18\ J/g-^{\circ} C\times (12.7-25)\ ^{\circ} C\\\\Q=-1542.42\ J

So, 1542.42 J of energy is transferred.

6 0
1 year ago
Justin is making a snack. He toasts a piece of bread and spreads peanut butter and jelly on it. Then he cuts an apple into sever
Leona [35]

Answer:

One chemical change- It was when he toasted the bread. The heat changed the bread so that it has the crust on the outside.

Explanation:

6 0
2 years ago
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500ml of a buffer solution contains 0.050 mol nahso3 and 0.031
nydimaria [60]

Answer:

The answers are explained below

Explanation:

a)

Given: concentration of salt/base = 0.031

concentration of acid = 0.050

we have

PH = PK a + log[salt]/[acid] = 1.8 + log(0.031/0.050) = 1.59

b)

we have HSO₃⁻ + OH⁻ ------> SO₃²⁻ + H₂O

Moles i............0.05...................0.01.................0.031.....................0

Moles r...........-0.01.................-0.01................0.01........................0.01

moles f...........0.04....................0....................0.041.....................0.01

c)

we will use the first equation but substituting concentration of base as 0.031 + 10ml = 0.031 + 0.010 = 0.041

Hence, we have

PH = PK a + log[salt]/[acid] = 1.8 + log(0.041/0.050) = 1.71

d)

pOH = -log (0.01/0.510) = 1.71

pH = 14 - 1.71 = 12.29

e)

Because the buffer solution (NaHSO3-Na2SO3) can regulate pH changes. when a buffer is added to water, the first change that occurs is that the water pH becomes constant. Thus, acids or bases (alkali = bases) Additional may not have any effect on the water, as this always will stabilize immediately.

4 0
2 years ago
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