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2 years ago

(S)-5,5-dibromo-3-fluoro-2-methyl-3-hexanol

Chemistry

2 answers:

blsea [12.9K]2 years ago

6 0

garri49 [273]2 years ago

6 0

Answer:

On the attached picture.

Explanation:

Hello,

By assuming you need such compound's structure, it is shown on the attached picture, in which an S (sinister-left) absolute configuration is specified. Such S accounts for a counter-clockwise arrangement at the third carbon as long as it has four different substituents: F, OH, CH and CH2.

Best regards.

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Convert 1.72 moles of magnesium carbonate to formula units

snow_tiger [21]

One mole any substance contains 6.022 ₓ 10²³ particles called Avogadro's Number.

The relation between moles and number of particles is given as,

# of particles = moles ₓ Avogadro's number

In our case the particles are formula units of MgCO₃. So, 1 mole of MgCO₃ contain 6.022 ₓ 10²³ formula units, then the number of formula units in 1.72 moles are calculated as,

# of formula units = 1.72 mol ₓ 6.022 ₓ 10²³ formula units / mol

# of formula units = 1.035 ₓ 10²⁴ Formula Units

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2 years ago

A can of soda contains many ingredients, including vanilla, caffeine, sugar, and water. Which ingredient is the solvent? caffein

tangare [24]

Answer:

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Explanation:

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22. How many atoms are there in 344.75 g of gold nugget? a. 1.05 x 10 to the power of 24 atoms b. 1.05 x 10 to the power of 23 a

mixas84 [53]

Answer:

1.053×10²⁴ atoms of gold

Explanation:

Hello,

Gold nugget are usually the natural occurring gold and they contain 85% - 90% weight of pure gold.

In this question, we're required to find the number of atoms in 344.75g of a gold nugget.

We can use mole concept relationship between Avogadro's number and molar mass.

1 mole = molar mass

Molar mass of gold = 197 g/mol

1 mole = Avogadro's number = 6.022 × 10²³ atoms

Number of mole = mass / molar mass

Mass = number of mole × molar mass

Mass = 1 × 197

Mass = 197g

197g is present in 6.022×10²³ atoms

344.75g will contain x atoms

x = (344.75 × 6.022×10²³) / 197

X = 1.053×10²⁴ atoms

Therefore 344.75g of gold nugget will contain 1.053×10²⁴ atoms of gold

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irina1246 [14]

Answer: $9.11\times 10^{-31}kg$

Explanation:

Significant figures : The figures in a number which express the value or the magnitude of a quantity to a specific degree of accuracy is known as significant digits.

Rules for significant figures:

Digits from 1 to 9 are always significant and have infinite number of significant figures.

All non-zero numbers are always significant.

All zero’s between integers are always significant.

All zero’s after the decimal point are always significant.

All zero’s preceding the first integers are never significant.

Thus $9.11\times 10^{-31}kg$ has three significant figures

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