Answer:
Mole fraction N₂ = 0.336
Explanation:
Mole fraction of a gas can be determined in order to know the partial pressure of the gas, and the total pressure, in the mixture.
Total pressure in the mixture: Sum of partial pressure from all the gases
Total pressure = 183 mmHg + 443 mmHg + 693 mmHg =1319 mmHg
Mole fraction N₂ = Partial pressure N₂ / Total pressure
443 mmHg / 1319 mmHg = 0.336
Remember that mole fraction does not carry units
Answer:
1.59mol/L
Explanation:
Data obtained from the question include:
Mass of MgCl2 = 151g
Volume of water(solvent) = 1L
Now, let us calculate the number of mole of MgCl2. This is illustrated below:
Molarity Mass of MgCl2 = 24 + (2x35.5) = 24 + 71 = 95g/mol
Mass of MgCl2 = 151g
Number of mole of MgCl2 =?
Number of mole = Mass /Molar Mass
Number of mole of MgCl2 = 151/95
Number of mole of MgCl2 = 1.59mole
Now we can calculate the molarity of MgCl2 as follow:
Mole = 1.59mole
Volume = 1L
Molarity =?
Molarity = mole /Volume
Molarity = 1.59/1
Molarity = 1.59mol/L
Answer:
Half life = 1600 years
Explanation:
Given data:
Total mass of sample = 45.00 g
Mass remain = 5.625 g
Time period = 4800 years
Half life of radium-226 = ?
Solution:
First of all we will calculate the number of half lives passes,
At time zero 45.00 g
At first half life = 45.00 g/ 2= 22.5 g
At 2nd half life = 22.5 g/ 2 = 11.25 g
At 3rd half life = 11.25 g/ 2= 5.625 g
Half life:
Half life = Time elapsed / number of half lives
Half life = 4800 years / 3
Half life = 1600 years
Answer:
Ag+
Explanation:
anode: 2AgNO3(l)⟶Ag(aq)+NO3(g)
