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neonofarm [45]
1 year ago
9

Ammonia reacts with hypobromite, obr, by the reaction 2nh3 3obr n n2 3br 3h2o. what is the molarity of a hypobromite solution if

1.00 ml of the obr solution reacts with 1.69 mg of nh3
Chemistry
1 answer:
Aliun [14]1 year ago
8 0

The balanced chemical equation representing the reaction of ammonia with hypobromite is:

2NH_{3} (g)+3OBr^{-}(aq)-->N_{2}(g)+3Br^{-}(aq)+3H_{2}O(l)

The mass of NH_{3}=1.69mg

Moles of NH_{3}=1.69mg*\frac{1g}{1000mg}* \frac{1mol}{17.03g} =9.92*10^{-5}molNH_{3}

Calculating the moles hypobromite that would react with 9.92*10^{-5}molNH_{3}:

9.92*10^{-5}molNH_{3}*\frac{3molOBr^{-} }{2molNH_{3}}=   1.488*10^{-4}mol OBr^{-}

Volume of hypobromite required for titration = 1.00 mL

Molarity of hypobromite solution = \frac{1.488*10^{-4}molOBr^{-}}{1.00mL} *\frac{1000mL}{1L} =0.1488mol/L

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See figure 1

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