Answer:
Explanation:
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In this case, given the neutralization of the acetic acid as a weak one with sodium hydroxide as a strong base, we can see how the moles of the both of them are the same at the equivalence point; thus, it is possible to write:
Thus, we solve for the molarity of the acid to obtain:
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Answer:
Following are the answer to this question:
Explanation:
In the given question information is missing, that is equation which can be defined as follows:
- Growing temperatures may change its connection to just the way which consumes thermal energy in accordance with Le chatelier concepts Potential connection is endothermic. Answer: shifts to the right
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Kc are described as a related to the concentration by the intensity of both the reaction for each phrase which reaches a power equal towards its stoichiometric equation coefficient Kc = \frac{product}{reactant}
It increases [product] but reduces [reactant] Therefore, Kc increases
"<span>30.4 ppm > 4 ppm, unsafe to drink" is the one among the following choices given in the question that shows that the water should be declared unsafe for drinking. The correct option among all the options that are given in the question is the third option or the penultimate option. I hope that the answer has helped you.</span>
Answer:
5.63 mol.
Explanation:
- The balanced chemical equation between NO₂ and H₂O is:
<em>3NO₂(s) + H₂O(l) → 2HNO₃(aq) + NO(g),
</em>
It is clear that 3 mol of NO₂ reacts with 1 mol of H₂O to produce 2 mol of HNO₃ and 1 mol of NO.
<em>Water is present as an excess reactant and NO₂ is limiting reactant.</em>
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- To find the no. of moles of HNO₃ produced:
3 mol of NO₂ produces → 2 mol of HNO₃, from stichiometry.
8.44 mol of NO₂ produces → ??? mol of HNO₃.
∴ The no. of moles of HNO₃ are formed = (8.44 mol)(2 mol)/(3 mol) = 5.63 mol.
At the first reaction when 2HBr(g) ⇄ H2(g) + Br2(g)
So Kc = [H2] [Br2] / [HBr]^2
7.04X10^-2 = [H2][Br] / [HBr]^2
at the second reaction when 1/2 H2(g) + 1/2 Br2 (g) ⇄ HBr
Its Kc value will = [HBr] / [H2]^1/2*[Br2]^1/2
we will make the first formula of Kc upside down:
1/7.04X10^-2 = [HBr]^2/[H2][Br2]
and by taking the square root:
∴ √(1/7.04X10^-2)= [HBr] / [H2]^1/2*[Br]^1/2
∴ Kc for the second reaction = √(1/7.04X10^-2) = 3.769
