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Aleonysh [2.5K]

2 years ago

10

A student has two compounds in two separate bottles but with no labels on either one. One is an unbranched alkane, octane, C8H18

; the other is 1-hexene, an unbranched alkene, C6H12. Based on your observations in this experiment, tell what you should see in the following tests: (a)- Water solubility (b)- Ligroin solubility (c)- Combustion (d)- Density versus water (e)- Bromine test (f)- Permanganate test

1 answer:

Aleks [24]2 years ago

7 0

Answer:

a) both substances are insoluble in water

b) both substances are soluble in ligroin

c) both substances suffer combustion, octane produces more CO₂ than hexene.

d) both substances are less dense than waterl, with hexene having the lowest density.

e) only hexene would react with bromine

f) only hexene would react with permanganate

Explanation:

a) both substances are non-polar and water is polar

b) both substances are non-polar and lingroin is non-polar

c) C₈H₁₈ + 17.5O₂ → 8CO₂ + 9H₂O

C₆H₁₂ + 9O₂ → 6CO₂ + 6H₂O

d) water = 997 kg/m³

ocatne = 703 kg/m³

hexene = 673 kg/m³

e) bromine test is used to detect unsaturations

f) permanganate test is used to detect unsaturations

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If 36.0 g of NaOH (MM = 40.00 g/mol) are added to a 500.0 mL volumetric flask, and water is added to fill the flask, what is the

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Answer:

Molarity of NaOH = 1.8 M.

Explanation:

From the question given above, the following data were obtained:

Mass of NaOH = 36 g

Molar mass of NaOH = 40 g/mol

Volume = 500 mL

Molarity of NaOH =?

Next, we shall determine the number of mole in 36 g of NaOH. This can be obtained as follow:

Mass of NaOH = 36 g

Molar mass of NaOH = 40 g/mol

Mole of NaOH =?

Mole = mass / molar mass

Mole of NaOH = 36 / 40

Mole of NaOH = 0.9 mole

Next, we shall convert 500 mL to L. This can be obtained as follow:

1000 mL = 1 L

Therefore,

500 mL = 500 mL × 1 L / 1000 mL

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Finally, we shall determine the molarity of NaOH. This can be obtained as follow:

Mole of NaOH = 0.9 mole

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Molarity of NaOH =?

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Answer:

The true statements are:

The solution is acidic

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$10^{-10.53}=[OH^-]$

Explanation:

The pH of the solution is defined as negative logarithm of hydrogen ion concentration present in the solution .

$pH=-\log[H^+]$

The pH value more 7 means that hydrogen ion concentration is less ,alkaline will be the solution.
The pH value less 7 means that hydrogen ion concentration is more ,acidic will be the solution.
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The pH of the solution = ?

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