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2 years ago

The rate of disappearance of HCl was measured for the following reaction:

Chemistry

1 answer:

AURORKA [14]2 years ago

6 0

Answer: (a) 0.000083M/s, 0.000069M/s, 0.000052M/s, 0.000034M/s

(b) average reaction rate between t=0.0min to t=430.0min =0.000049M/s

(c) The average rate between t=54.0 and t=215.0min is greater than the average rate between t=107.0 and t=430.0min

Explanation:

Average reaction rate = change in concentration / time taken

(a) after 54mins, t = 54*60s = 3240s

average reaction rate = (1.58 - 1.85)M / (3240 * 0.0)s

= -0.27M/3240

= 0.000083M/s

after 107mins, t = 107*60s = 6420s

average reaction rate = (1.36 - 1.58)M/ (6420 - 3240)s

= -0.22M/3180s

= 0.000069M/s

after 215mins, t = 215*60s = 12900s

average reaction rate = (1.02 - 1.36)M/ (12900 - 6420)s

= -0.34M/6480s

= 0.000052M/s

after 430mins,t = 430*60 = 25800s

average reaction rate = (0.580 - 1.02)M / (25800 - 12900)s

= -0.44M/12900s

= 0.000034M/s

(b) average reaction rate between t=0.0min to t=430.0min

= (0.580 - 1.85)M/ (25800 - 0.0)s

= -1.27M/25800s

=0.000049M/s

= (1.02 - 1.58)M / (12900 - 3240)s

= -0.56M/9660s

= 0.000058M/s

average reaction rate between t=107.0 and t=430.0min

= (0.580 - 1.36)M / (25800 - 6420)s

= 0.78M /19380s

= 0.000040M/s

Therefore the average rate between t=54.0 and t=215.0min is greater than the average rate between t=107.0 and t=430.0min

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Three 1.0-l flasks, maintained at 308 k, are connected to each other with stopcocks. initially the stopcocks are closed. one of

Licemer1 [7]

Answer:

0.6103 atm.

Explanation:

We need to calculate the vapor pressure of each component after the stopcocks are opened.

Volume after the stopcocks are opened = 3.0 L.

1) For N₂:

P₁V₁ = P₂V₂

P₁ = 1.5 atm & V₁ = 1.0 L & V₂ = 3.0 L.

P₂ of N₂ = P₁V₁ / V₂ = (1.5 atm) (1.0 L) / (3.0 L) = 0.5 atm.

2) For H₂O:

Pressure of water at 308 K is 42.0 mmHg.

we need to convert from mmHg to atm: (1.0 atm = 760.0 mmHg).

P of H₂O = (1.0 atm x 42.0 mmHg) / (760.0 mmHg) = 0.0553 atm.

We must check if more 2.2 g of water is evaporated,

n = PV/RT = (0.0553 atm) (3.0 L) / (0.082 L.atm/mol.K) (308 K) = 0.00656 mole.

m = n x cmolar mass = (0.00656 mole) (18.0 g/mole) = 0.118 g.

It is lower than the mass of water in the flask (2.2 g).

3) For C₂H₅OH:

Pressure of C₂H₅OH at 308 K is 102.0 mmHg.

we need to convert from mmHg to atm: (1.0 atm = 760.0 mmHg).

P of C₂H₅OH = (1.0 atm x 102.0 mmHg) / (760.0 mmHg) = 0.13421 atm.

We must check if more 0.3 g of C₂H₅OH is evaporated,

n = PV/RT = (0.13421 atm) (3.0 L) / (0.082 L.atm/mol.K) (308 K) = 0.01594 mole.

m = n x molar mass = (0.01594 mole) (46.07 g/mole) = 0.7344 g.

It is more than the amount in the flask (0.3 g), so the pressure should be less than 0.13421 atm.

We have n = mass / molar mass = (0.30 g) / (46.07 g/mole) = 0.00651 mole.

So, P of C₂H₅OH = nRT / V = (0.00651 mole) (0.082 L.atm/mole.K) (308.0 K) / (3.0 L) = 0.055 atm.

So, total pressure = P of N₂ + P of H₂O + P of C₂H₅OH = 0.5 atm + 0.0553 atm + 0.055 atm = 0.6103 atm.

3 0

1 year ago

Andre, a physics undergraduate, enters a coffee shop that is holding a contest. Customers who guess the number of coffee beans i

RideAnS [48]

Answer: 8 coffee beans

Explanation: this calculation can only be achieved if you are good

With your conversation table.

16fl oz is the same as 16 US fluid ounce. The question is to determine how many centimeter can be equall to 16fl oz.

Stage 1:

Convert 16 US fluid to milliliter

1 US fluid = 29.574mililiter.

Therefore (16fl oz × 29.574ml)÷ 1fl oz= 473.184ml

Stage 2:

Convert milliliter to cubic centimeter

1 milliliter = 1 cubic centimeter

Therefore 473.184ml= 473.184cc

Stage 3:

Convert cubic centimeter to centimeter

1 Cubic centimeter is the volume 1 centimeter of a length side occupies

Volume= the length of the three sides of a shape.

Therefore

Volume= lenght^3

Making length the subject of the formula it becomes

Length =Cube root of volume

Length= 3√volume

Therefore

Length = 3√473.184= 7.793cm

Approximately 8cm

This means the mug is 8cm in length

Stage 4:

Since Andre assumption is that coffee Bean is about 1cm and from the calculation the mug is 8cm, which means about eight coffee Beans will fill the flask.

Andre should submit 8 coffee beans

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2 years ago

Zinc has a specific heat capacity of 0.390 J/goC. What is its molar heat capacity? Enter your answer numerically to three signif

ch4aika [34]

Answer:

The answer to your questions is Cm = 25.5 J/mol°C

Explanation:

Data

Heat capacity = 0.390 J/g°C

Molar heat capacity = ?

Process

1.- Look for the atomic number of Zinc

Z = 65.4 g/mol

2.- Convert heat capacity to molar heat capacity

(0.390 J/g°C)(65.4 g/mol)

- Simplify and result

Cm = 25.5 J/mol°C

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1 year ago

What is the advantage of having large vertebrae at the base of the vertebral column?

WINSTONCH [101]

The advantage of having large vertebrae at the base of the vertebral column is having stability in terms of the center of gravity of the animal. If the animal has a large vertebrae, then it has an excellent balance and strength.

3 0

1 year ago

Write a net ionic equation to show how piperidine, c5h11n, behaves as a base in water.

lidiya [134]

$C_5H_{11}N + H2O ---\ \textgreater \ C_5H_{11}NH^{+} + OH^{-}$

Nitrogen lone pair will act as a base,removing H+ from water leaving behind OH- ion.
Why ?
Because N is a better donor than O.

7 0

2 years ago