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2 years ago

Which is the stronger acid in each of the following pairs? Explain your reasoning.

Chemistry

1 answer:

Makovka662 [10]2 years ago

6 0

Answer:p-hydroxybenzaldehyde is stronger acid to phenol

para-cyanophenol is stronger acid to meta-cyanophenol

o-fluorophenol is stronger acid to p-fluorophenol.

Explanation:

The PKa tool relative to Ph are used to contrast the pairs.

The pKa of phenol is 10. The pKa of p-hydroxybenzaldehyde is 9.24

The pKa for meta-cyanophenol is 8.61 and the pKa for para-cyanophenol is 7.95.

The pKa value of o-fluorophenol is 8.7, while that of the p-fluorophenol is 9.9. It's obvious that the inductive effect is more dominant at ortho-position, which results in a more acidic nature

The pKa is the pH value at which a chemical species will accept or donate a proton. The lower the pKa, the stronger the acid and the greater the ability to donate a proton in aqueous solution.

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If 0.15 mol of I2 vapor can effuses through an opening in a heated vessel in 36 sec, how long will it take 0.15 mol of Cl2 to ef

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<u>Answer:</u> The amount of time required by chlorine gas to effuse is 19 seconds.

<u>Explanation:</u>

Rate of a gas is defined as the amount of gas displaced in a given amount of time.

$\text{Rate}=\frac{n}{t}$

To calculate the rate of diffusion of gas, we use Graham's Law.

This law states that the rate of effusion or diffusion of gas is inversely proportional to the square root of the molar mass of the gas. The equation given by this law follows the equation:

$\text{Rate of effusion}\propto \frac{1}{\sqrt{\text{Molar mass of the gas}}}$

So,

$\left(\frac{\frac{n_{Cl_2}}{t_{Cl_2}}}{\frac{n_{I_2}}{t_{I_2}}}\right)=\sqrt{\frac{M_{I_2}}{M_{Cl_2}}}$

We are given:

Moles of iodine gas = 0.15 moles

Moles of chlorine gas = 0.15 moles

Time taken by iodine gas = 36 seconds

Molar mass of iodine gas = 254 g/mol

Molar mass of chlorine gas = 71 g/mol

Putting values in above equation, we get:

$\left(\frac{\frac{0.15}{t_{Cl_2}}}{\frac{0.15}{36}}\right)=\sqrt{\frac{254}{71}}\\\\\frac{0.15}{t_{Cl_2}}\times \frac{36}{0.15}=1.89\\\\t=19s$

Hence, the amount of time required by chlorine gas to effuse is 19 seconds.

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2 years ago

A bird building a nest for its young is a reproductive strategy. Based on this example, what do you think the term “reproductive

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Matt did an experiment to study the solubility of two substances. He poured 100 mL of water at 20 °C into each of two beakers la

Black_prince [1.1K]

Part 1 : Answer is only B substance is soluble in water.

In this experiment undissolved mass of each substance was measured. According to the given data, undissolved mass of substance B at 20 °C is 10 g while A is 50 g. Since, the initial added mass of each substance is 50 g, we can see that substance A is not soluble in water since the undissolved mass is 50 g.

Part 2 : Substance A is not soluble in water and substance B is soluble in water.

According to the given data, the undissolved mass of substance A remains as same as initial added mass, 50 g throughout the temperature range from 20 ° to 80 °C. Hence, we can conclude that substance A is not soluble in water.

But, according to the data, undissolved mass of substance B at 20 °C is 10 g. That means, 40 g of substance B was dissolved in water. When the temperature increases the undissolved mass of substance B decreases. Hence, we can conclude that substance B is soluble in water and solubility increases with temperature.

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Calculate the mass of the zinc that reacts with 4.11 g of hydrochloric acid to form 9.1 g of zinc chloride and 3.97 g of hydroge

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Answer: Mass of zinc that reacts with 4.11 g of hydrochloric acid to form 9.1 g of zinc chloride and 3.97 g of hydrogen gas is 8.96 g

Explanation:

According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side. Thus chemical equations are balanced.

$Zn+2HCl\rightarrow ZnCl_2+H_2$

Given: mass of hydrochloric acid = 4.11 g

Mass of products = Mass of zinc chloride + mass of hydrogen = 9.1 g + 3.97 g = 13.07 g

As mass of reactant = mass of products

mass of hydrochloric acid + mass of zinc = Mass of zinc chloride + mass of hydrogen

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