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blagie [28]
1 year ago
5

Moving from boron to carbon, the intensity of the bulb __

Chemistry
1 answer:
AleksandrR [38]1 year ago
7 0

Explanation:

The thickness of the frosting Moving from boron to carbon, the intensity of the bulb blank because Z increases from blank to blank. The thickness of the frosting blank because the core electron configuration is the same for both atoms. because the core electron configuration is the same for both atoms.

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Calculate the average time it took the car to travel 0.25 What is the average time it took the car to travel 0.25
DedPeter [7]

Answer:

Explanation:

idk why all u guys like trump who do.. hes just a big pain in the a*s.

8 1
1 year ago
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How many grams of copper (II) nitrate would be produced from 0.80 g of copper metal reacting with excess nitric acid?
zaharov [31]

Answer:

m_{Cu(NO_3)_2}=2.36 gCu(NO_3)_2

Explanation:

Hello!

In this case, since the chemical reaction between copper and nitric acid is:

2HNO_3+Cu\rightarrow Cu(NO_3)_2+H_2

By starting with 0.80 g of copper metal (molar mass = 63.54 g/mol) and considering the 1:1 mole ratio between copper and copper (II) nitrate (molar mass = 187.56 g/mol) we can compute that mass via stoichiometry as shown below:

m_{Cu(NO_3)_2}=0.80gCu*\frac{1molCu}{63.54gCu} *\frac{1molCu(NO_3)_2}{1molCu} *\frac{187.56gCu(NO_3)_2}{1molCu(NO_3)_2} \\\\m_{Cu(NO_3)_2}=2.36 gCu(NO_3)_2

However, the real reaction between copper and nitric acid releases nitrogen oxide, yet it does not modify the calculations since the 1:1 mole ratio is still there:

4HNO_3+Cu\rightarrow Cu(NO_3)_2+2H_2O+2NO_2

Best regards!

7 0
1 year ago
How many moles of AgNO3 must react to form 0.854 mol Ag?
kipiarov [429]
The answer:
<span>The equation of its dissolution in water is: AgNO3 → Ag + (aq)  +  NO3- (aq)

and     </span>AgNO3 →   Ag + (aq)  +  NO3- (aq)
          1 mol          1mol                1mol 
             ?  --------   0.854mo
so for finding the value, it is sufficients to complute 1 x 0.854 mol =0.854 mol
so,  0.854 mol is required for the reaction to form 0.854 mol of Ag

5 0
2 years ago
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To win in a qualifying round in a duck race, a duck's rate of change needs to be 35.4 meters/second. Kate was training her duck
Setler [38]

Answer:

i believe that 14  at a higher rate is the answer

Explanation:

3 0
1 year ago
What is the mass in grams of 7.5 x 10^15 atoms of nickel?
satela [25.4K]
Atomic mass Ni = 58.69 a.m.u

58.69 g ----------------- 6.02x10²³ atoms
?? g --------------------- 7.5x10¹⁵ atoms

58.69x (7.5x10¹⁵) / 6.02x10²³

=> 7.31x10⁻⁷ g
6 0
2 years ago
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