Answer : Total molecules that will be needed to visualize a single egg will be 78500 molecules of dye.
Explanation : As a single egg cell has an approximately diameter of 100 μm.
We can use this formula to calculate area of the cell membrane;
A = π
;
We can take π as 3.14 and we get;
A = 3.14 X
Soving we get;
A = 7850 μ
Here we have to calculate the amount of dye molecules which will be needed for 10 fluorescent molecules / μ
but;
here 1 μ
= 7850 μ
dye molecules.
Therefore, 10 fluorescent molecules will need;
7850 X 10 = 78500 molecules of dye.
Therefore, the answer is 78500 molecules of dye.
Answer:
20.2 g silver placed in 21.6 mL of water and 20.2 g copper placed in 21.6 mL of water
Explanation:
Since the density formula is mass divided volume, you can calculate the density of each of the components of the group and see which of all the groups are equal
In the group
density Ag=20.2 g silver/21.6ml H2O=0.9352g/ml
density Cu=20.2 g copper/21.6ml H2O=0.9352 g/ml
Answer:
30.6 g of C is formed.
Explanation:
2A + B → C
Average rate of reaction = 2[A]/Δt = [B]/Δt = [C]/Δt
Average rate of reaction = [C]/Δt
Average rate of reaction = 15 g / 9 min
Average rate of reaction = 1.7 g of C / min
Average rate of reaction = [C]/Δt
[C] = Average rate of reaction x Δt
[C] = 1.7 g of C / min x 18 min
[C] = 30.6 g of C