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2 years ago

Which of the following statements best describes the properties of aluminum-28?

Chemistry

1 answer:

Contact [7]2 years ago

5 0

d. When aluminum-28 undergoes beta decay, silicon-28 is produced.

Explanation:

When the nuclei of aluminium-28 decays, it produces silicon- 28:

Aluminium ²⁸₁₃Al

Silicon 28 ²⁸₁₄Si

beta particle ⁰₋₁ $\beta$

²⁸₁₃Al → ²⁸₁₄Si + ⁰₋₁ $\beta$

This way, the mass and atomic number are conserved.

Conservation of mass number:

28 = 28 + 0, 28 = 28

13 = 14 -1 , 13 = 13

Learn more:

Balancing nuclear equations brainly.com/question/10094982

#learnwithBrainly

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The reading on a speedometer represents the average velocity of the car. True False

Sedbober [7]

Answer: False. Hope this helps!!

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2 years ago

A ground state hydrogen atom absorbs a photon of light having a wavelength of 93.7 nm.93.7 nm. What is the final state of the hy

sammy [17]

Answer:

Explanation:

Given that the formula is;

1/λ= R(1/nf^2 - 1/ni^2)

λ = 93.7 nm or 93.7 * 10^-9 m

R= 1.097 * 10^7 m-1

nf = ?

ni = 1

From;

ΔE = hc/λ

ΔE = 6.63 * 10^-34 * 3* 10^8/93.7 * 10^-9

ΔE = 21 * 10^-19 J

ΔE = -2.18 * 10^-18 J (1/nf^2 - 1/ni^2)

21 * 10^-19 J = -2.18 * 10^-18 J (1/nf^2 - 1/ni^2)

21 * 10^-19/-2.18 * 10^-18 = (1/nf^2 - 1/1^2)

-0.963 = (1/nf^2 - 1)

-0.963 + 1 = 1/nf^2

0.037 = 1/nf^2

nf^2 = (0.037)^-1

nf^2 = 27

nf = 5

7 0

2 years ago

Consider the following reactions and their respective equilibrium constants: NO(g)+12Br2(g)⇌NOBr(g)Kp=5.3 2NO(g)⇌N2(g)+O2(g)Kp=2

maxonik [38]

Answer:

Equilibrium constant of the given reaction is $1.3\times 10^{-29}$

Explanation:

$NO+\frac{1}{2}Br_{2}\rightleftharpoons NOBr$ .... $(K_{p})_{1}=5.3$

$2NO\rightleftharpoons N_{2}+O_{2}$ .... $(K_{p})_{2}=2.1\times 10^{30}$

The given reaction can be written as summation of the following reaction-

$2NO+Br_{2}\rightleftharpoons 2NOBr$

$N_{2}+O_{2}\rightleftharpoons 2NO$

......................................................................................

$N_{2}+O_{2}+Br_{2}\rightleftharpoons 2NOBr$

Equilibrium constant of this reaction is given as-

$\frac{[NOBr]^{2}}{[N_{2}][O_{2}][Br_{2}]}$

$=(\frac{[NOBr]}{[NO][Br_{2}]^{\frac{1}{2}}})^{2}(\frac{[NO]^{2}}{[N_{2}][O_{2}]})$

$=\frac{(K_{p})_{1}^{2}}{(K_{p})_{2}}$

$=\frac{(5.3)^{2}}{2.1\times 10^{30}}=1.3\times 10^{-29}$

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2 years ago

Read 2 more answers

What is the mass of 2.5 moles of hydrogen fluoride gas HF

Nady [450]

Answer:

You will get 5.0 g of hydrogen.

Explanation:

As with any stoichiometry problem, we start with the balanced equation.

2HF

→

SnF

Moles of H

2.5

mol Sn

1 mol H

mol Sn

2.5 mol H

Mass of H

2.5

mol H

2.016 g H

mol H

5.0 g H

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2 years ago

Describe how transpiration and respiration show interactions among Earth's system

stepladder [879]

Earth has 4 systems/ spheres which are known as Lithosphere(land), Biosphere(living things), Hydrosphere(water) and Atmosphere(air).

Transpiration is the process that interact with the Hydrosphere and Respiration is the process that interacts with the Atmosphere.

Transpiration is the process happening in plants which absorb and distribute water through their roots and release water in the form of vapors through their leaves. As this process involves Water, therefore this process interacts with the Hydrosphere.

Respiration is the process in which plants convert carbon dioxide to oxygen as a part of photosynthesis which was then inhaled by the animals. As this process involves Air, therefore this process interacts with the Atmosphere.

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2 years ago

Read 2 more answers