Answer:
B. It is formed by a repeating pattern of a single type of atom
Explanation:
i think thats answer may i get brainlest?
ANSWER: B. 20 grams since no matter was added or removed
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Answer:
Option A
Explanation:
Number of millimoles of Na3PO4 = 1 × 100 = 100
Number of millimoles of AgNO3 = 1 × 100 = 100
When 1 mole of Na3PO4 is dissociated we get 3 moles of sodium ions and 1 mole of phosphate ion
When 1 mole of AgNO3 is dissociated, we get 1 mole of Ag+ and 1 mole of NO3-
As Ag+ concentration is negligible, the dissociated Ag+ ion must have form the precipitate with phosphate ion and as number of moles of Ag+ and phosphate ion are same, therefore the concentration of phosphate ion must be negligible
Here as 100 millimoles of Na3PO4 is there, we get 300 millimoles of Na+ and 100 millimoles of PO43-
And as 100 millimoles of AgNO3 is there, we get 100 millimoles of Ag+ and 100 millimoles of NO3-
∴ Increasing order of concentration will be PO43- < NO3- < Na+
Answer:
The bond dissociation energy to break 4 bonds in 1 mol of CH is 1644 kJ
Explanation:
Since there are 4 C-H bonds in CH₄, the bond dissociation energy of 1 mol of CH₄ is 4 × bond dissociation energy of one C-H bond.
From the table one mole is C-H bond requires 411 kJ, that is 411 kJ/mol. Therefore, 4 C-H bonds would require 4 × 411 kJ = 1644 kJ
So, the bond dissociation energy to break 4 bonds in 1 mol of CH₄ is 1644 kJ
Answer:
1.59mol/L
Explanation:
Data obtained from the question include:
Mass of MgCl2 = 151g
Volume of water(solvent) = 1L
Now, let us calculate the number of mole of MgCl2. This is illustrated below:
Molarity Mass of MgCl2 = 24 + (2x35.5) = 24 + 71 = 95g/mol
Mass of MgCl2 = 151g
Number of mole of MgCl2 =?
Number of mole = Mass /Molar Mass
Number of mole of MgCl2 = 151/95
Number of mole of MgCl2 = 1.59mole
Now we can calculate the molarity of MgCl2 as follow:
Mole = 1.59mole
Volume = 1L
Molarity =?
Molarity = mole /Volume
Molarity = 1.59/1
Molarity = 1.59mol/L
