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kondaur [170]
2 years ago
14

Why does the pink color, which forms at the point where NaOH comes into contact with the solution (HCl) in the flask, disappear

more slowly near the endpoint?
Chemistry
1 answer:
Novay_Z [31]2 years ago
4 0
Answer is: because pH value of solution is changing.
Balanced chemical reaction: NaOH(aq) + HCl(aq) → NaCl(aq) + H₂O(l).
pH of sodium hydroxide solution is above seven (basic), when solution of hydrochloric acid is added, pH slowly dropping until it became neutral solution (pH is equal seven) and that is endpoint of titration.
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Which sweet tea would you expect to taste the sweetest? <br> Here is the clear picture
Olegator [25]

Answer: You're right, it's 8 M

Explanation: The higher the number, the sweater it is.

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2 years ago
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A sample of neon effuses from a container in 72 seconds. the same amount of an unknown noble gas requires 147 seconds. you may w
Alexxx [7]
The   second gas  is  identified  as  follows

by  Graham law  formula
let  the  unknown gas  be  represented  by  letter y

=time of  effusion of Neon/ time  of effusion of  y =   sqrt (molar mass of neon/molar  mass of y)

= 72  sec/ 147  sec =  sqrt( 20.18  g/mol/ y   g/mol)

square the  both  side  to  remove  the  square  root  sign

72^2/147^2  = 20.18 g/mol/y g/mol

=0.24 = 20.18g/mol/y g/mol

multiply  both side  by  y  g/mol
= 0.24  y g/mol = 20.18g/mol
divide both side  by  0.24 
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6 0
1 year ago
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According to the following reaction, how many moles of Fe(OH)2 can form from 175.0 mL of 0.227 M LiOH solution? Assume that ther
IgorC [24]

Answer:

0.020 moles of Fe(OH)_{2} can be formed

Explanation:

1. First determine the number of moles of LiOH.

Molarity is given by the following expression:

M=\frac{molesofsolute}{Litersofsolution}

Solving for moles of solute:

moles of solute = M * Liters of solution

Converting 175.0mL to L:

175.0mL*\frac{1L}{1000mL}=0.175L

Replacing values:

moles of solute = 0.227M*0.175L

moles of solute = 0.040

Therefore there are 0.040 moles of LiOH

2. Then write the balanced chemical reaction and use the stoichiometry of the reaction to calculate the number of moles of Fe(OH)_{2} produced:

FeCl_{2}(aq)+2LiOH(aq)=Fe(OH)_{2}(s)+2LiCl(aq)

As the problem says that there are excess of FeCl_{2}, the limiting reagent is the LiOH.

0.040molesLiOH*\frac{1molFe(OH)_{2}}{2molesLiOH}=0.020molesFe(OH)_{2} can be formed

3 0
2 years ago
A student has two samples of NaCl, each one from a different source. Assume that the only potential contaminant in each sample i
bija089 [108]

Answer:

The correct option is;

A. Which sample has the higher purity

Explanation:

The information given relate to the presence of two samples of NaCl, from different sources

The only potential contaminant in each of the sources = KCl

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Let the number of moles of KCl in the sample = X

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Each mole of KCl, will yield 35.453 g/mol per 74.5513 g/mol of KCl

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Therefore, the pure sodium chloride sample will yield more chlorine per unit mass of sample.

As such if the two samples have the same mass, the sample with the contaminant of KCl will yield less mass of chlorine per unit mass of the sample, from which the student will be able to tell the purity of the solution.

The sample with the higher purity will yield  a higher mass chlorine per unit mass of the sample.

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UkoKoshka [18]

Answer:

The answer is: A

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