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2 years ago

The bonds in the compound MgSO4 can be described as

1 answer:

7 0

C. Sulfur and oxygen (non metals) forms a covalent bond while the magnesium (a metal) will react with both non metals to form an ionic bond

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A chemist adds 180.0 mL of a 1.42M sodium carbonate (Na CO,) solution to a reaction flask. Calculate the millimoles of sodium ca

svet-max [94.6K]

Answer: The millimoles of sodium carbonate the chemist has added to the flask are 256

Explanation:

Molarity is defined as the number of moles dissolved per liter of the solution.

To calculate the number of moles for given molarity, we use the equation:

$\text{Molarity of the solution}=\frac{\text{milli moles of solute}}{\text{Volume of solution in ml}}$ .....(1)

Molarity of $BaCl_2$ solution = 1.42 M

Volume of solution = 180.0 mL

Putting values in equation 1, we get:

$1.42M=\frac{\text{milli moles of }BaCl_2}{180.0ml}\\\\\text{milli moles of }BaCl_2}={1.42M\times 180.0ml}=256milli mol$

Thus the millimoles of sodium carbonate the chemist has added to the flask are 256.

6 0

1 year ago

William adds two values, following the rules for using significant figures in computations. He should write the sum of these two

Lunna [17]

<span>when it comes to adding or subtracting numbers, his final answer should have the same number of decimal places as the least precise value.
For example if you add 2 numbers; 10.443 + 3.5 , 10.443 has 3 decimal places and 3.5 has only one decimal place.
Therefore 3.5 is the less precise value.
So when adding these 2 values the final answer should have only one decimal place.
after adding we get 13.943 but it can have upto one decimal place. then the second decimal place is less than 5 so the answer should be rounded off to 13.9.
the answer is the same number of decimal places as the least precise value</span>

6 0

1 year ago

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By mistake, a quart of oil was dumped into a swimming pool that measures 25.0 m by 30.0 m. The density of the oil was 0.750 g/cm

kondor19780726 [428]

The oil slick thick = 1.256 x 10⁻⁴ cm

<h3>Further explanation</h3>

Volume is a derivative quantity derived from the length of the principal

The unit of volume can be expressed in liters or milliliters or cubic meters

The conversion is

1 cc = 1 cm3

1 dm = 1 Liter

1 L = 1.06 quart

<em>so for 1 quart = 0.943 L</em>

$\tt 0.943~L=0.943\times 10^{-3}m^3$

Volume of oil dumped = volume of swimming pool

$\tt 0.943\times 10^{-3}~m^3=25\times 30\times h(h=thick)\\\\h=\dfrac{0.943\times 10^{-3}}{750~m^2}=1.257\times 10^{-6}~m=\boxed{\bold{1.256\times 10^{-4}~cm}}$

3 0

1 year ago

What is the concentration of Iodine I2 molecules in a solution containing 2.54 g of iodine 250 cm3 of solution? A 0.01mol/dm3 B

gulaghasi [49]

Answer:

C. 0.04 moles per cubic decimeter.

Explanation:

The molar mass of the Iodine is 253.809 grams per mole and a cubic decimeter equals 1000 cubic centimeters. The concentration of Iodine ( $c$ ), measured in moles per cubic decimeter, can be determined by the following formula:

$c = \frac{m}{M\cdot V}$ (1)

Where:

$m$ - Mass of iodine, measured in grams.

$M$ - Molar mass of iodine, measured in grams per mol.

$V$ - Volume of solution, measured in cubic decimeters.

If we know that $m = 2.54\,g$ , $M = 253.809\,\frac{g}{mol}$ and $V = 0.25\,dm^{3}$ , then the concentration of iodine in a solution is:

$c = \frac{2.54\,g}{\left(253.809\,\frac{g}{mol} \right)\cdot (0.25\,dm^{3})}$

$c = 0.04\,\frac{mol}{dm^{3}}$

Hence, the correct answer is C.

3 0

1 year ago

A 0.12m solution of an acid that ionizes only slightly in solution would be termed _____.

Fittoniya [83]

A 0.12 M solution of an acid that only slightly ionizes in solution would be termed a weak acid. Weak acids are acids which do not completely dissociate in water. Thus lowering the presence of hydronium ions which measures the pH of an acid. <span />

5 0

1 year ago

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