Answer:
The open system evaporates the solvent in the solution
Explanation:
An open system is a system in which exchange of materials and energy can occur. If a TLC set up is left open, then the set up constitutes an open system.
During TLC, the sample is dotted on the plate and inserted into a suitable solvent. The solvent moves up the plate and achieves the required separation of the mixture.
Most of these solvents used used TLC are volatile organic compounds. Therefore, if the TLC set up is left open, the solvent will evaporate leading to poor results after running the TLC experiment.
Answer:
The half-life varies depending on the isotope.
Half-lives range from fractions of a second to billions of years.
The half-life of a particular isotope is constant.
<span>30.%
Determine the molar mass of NH3 and NO
Atomic weight nitrogen = 14.0067
Atomic weight hydrogen = 1.00794
Atomic weight oxygen = 15.999
Molar mass NH3 = 14.0067 + 3 * 1.00794 = 17.03052 g/mol
Molar mass NO = 14.0067 + 15.999 = 30.0057 g/mol
Moles NH3 = 8.5 / 17.03052 = 0.499103962 mol
Moles NO = 4.5 / 30.0057 = 0.149971505 mol
Looking at the balanced equation, for every mole of NH3 consumed, you should get one mole of NO. So if we had 100% yield, we should have 0.499103962 moles of NO. But we don't. The percent yield is a simple matter of division by what we did get by what we should get. So
0.149971505 / 0.499103962 = 0.300481497 = 30.0481497%
Rounding to 2 significant figures gives 30.% yield.</span>
Answer:
The description including its given problem is outlined in the following section on the clarification.
Explanation:
The given values are:
RBCC = 0.12584 nm
RFCC = 0.12894 nm
The unit cell edge length (ABCC) as well as the atomic radius (RBcc) respectively connected as measures for BCC (α-phase) structure:
√3 ABCC = 4RBCC
⇒ ABCC = 
⇒ = 
⇒ = 
Likewise AFCC as well as RFCC are interconnected by
√2AFCC = 4RFCC
⇒ AFCC = 
⇒ = 
⇒ = 
Now,
The Change in Percent Volume,
= 
= 
= 
= 
= 
Note: percent = %
Answer:
very unlikely to be found in dirt
Explanation:
That combination has a ratio of ¹⁴N to ¹⁵N of 10:4 = 2.5: 1. The most ¹⁵N enriched natural material has a ratio of ¹⁴N to ¹⁵N on the order of 250 : 1 or higher. The combination shown is very unlikely to be found in dirt.
