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Mazyrski [523]
2 years ago
11

A student measures the absorbance of a solution containing FeSCN2 ion using a spectrophotometer. The cuvette used by the student

has two frosted walls and two transparent walls. The student properly orients the cuvette so that the path of the light goes through the transparent sides of the cuvette when calibrating the spectrophotometer. How will the measured absorbance of the FeSCN2 be affected if the student incorrectly orients the cuvette so that the path of the light is through the frosted sides of the cuvette
Chemistry
1 answer:
suter [353]2 years ago
6 0

Answer:

The measured absorbance will be too large.  

Explanation:

Fe³⁺(aq) + SCN⁻(aq) ⟶Fe(SCN)²⁺(aq)

A = log₁₀(I₀/I)

If the student orients the cuvette so that the path of the light is through the frosted sides of the cuvette, little light will be able to reach the detector.

The measured intensity (I) will be quite small, so the absorbance (A) will be unusually large.

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Write an equation for the formation of bf3(g) from its elements in their standard states.
blagie [28]
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On the other hand, fluorine is diatomic. Therefore, its formula is F2

Now, the basic unbalanced equation is:
B + F2 .........> BF3

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Balancing the equation, we will reach the following balanced reaction:
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7 0
2 years ago
A gas occupies 22.4 l at stp and 14.5 l at 100c and 2.00 atm pressure. how many moles of gas did the system gain or lose?
azamat
<span>At standard temperature and pressure 22.4 l of an ideal gas would contain 1 mole. in order to find the change in moles we must look at the ideal gas law PV=nRT where P=Pressure V=volume n=Moles R= Gas constant T= Temperature. To simplify this equation we will be using the gas constant at .08206 L-atm/mol-K. We must first convert 100c to k which is 373.15. Then we can plug the values into our equation which gives us (2atm)(14.5 l)=(n)(.08206 L-atm/mol-K)(373.15). After some basic algebra we get the moles to equal roughly .95 which is .05 moles less than our original system.</span>
6 0
2 years ago
A gold wire has a diameter of 1.00 mm. What length of this wire contains exactly 1.00 mol of gold? (density of Au = 17.0 g/cm3)
allochka39001 [22]

Answer:

The answer to your question is 7160 cm

Explanation:

Data

diameter = 1 mm

length = ?

amount of gold = 1 mol

density = 17 g/cm³

Process

1.- Get the atomic mass of gold

Atomic mass = 197 g

then, 197g ------------ 1 mol

2.- Calculate the volume of this wire

density = mass/volume

volume = mass/density

volume = 197/17

volume = 5.7 cm³

3.- Calculate the length of the wire

Volume = πr²h

solve for h

h = volume /πr²

radius = 0.05 cm

substitution

h = 5.7/(3.14 x 0.05²)

h = 5.7 / 0.0025

h = 7159.2 cm ≈ 7160 cm

8 0
2 years ago
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Jobisdone [24]

Answer:

It is required answer.

Explanation:

Given that :

1. using balanced chemical equation:

ammonium acetate:

The balanced equation is:

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when ammonia gas dissolves in water then we get the base in form of ammonium hydroxide.

When  NH₄OH reacts with CH₃COOH then we get ammonium acetate and water

NH₄OH + CH₃COOH ===> [CH₃COO]- & NH₄+ & H₂O

So, we can say that,

when we are adding an acid and a base together then we get the product of H₂O and given elements.

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the balanced equation is

H₂SO4+ Ba(OH)₂--> BaSO₄+ 2H₂O

when acid and base reacts together than we get barium sulphate and water

when sulfuric acid and barium hydroxide.

Hence, it is required answer.

8 0
2 years ago
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I'm going to suppose you want the adjusted chemical reaction, using the formulas of the compounds. You can see it in the image attached.

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