All categories

2 years ago

Based on the activity series provided, which reactants will form products?

Chemistry

2 answers:

lorasvet [3.4K]2 years ago

8 0

Idk man, but people are saying its Br2<span> + NaCl

hope it helped you</span>

allsm [11]2 years ago

6 0

Answer: CuI₂ + Br₂

Explanation:

1) The activity series F > Cl > Br > I means that F is the most active and I is the least active of those four elements (the halogens, group 17 in the periodic table).

The activity is a measure of how eager is an element to react compared to other elements in the series in a single replacement reaction.

2) Choice 1: CuI₂ + Br₂

Since the activity of Br is higher than that of I, Br will react with CuI₂, displacing I, which will be left alone, as per this chemical equation:

CuI₂ + Br₂ → CuBr₂ + I₂

Being I less active than Br, it cannot displace Br in CuBr₂.

3) Choice 2: Cl₂ + AlF₃

Being Cl less active than F, the former will not displace the latter, and the reaction will not proceed.

4) Choice 3: Br₂ + NaCl

Again, being Br less active than Cl, the former will not displace the latter, and the reaction will not proceed.

5) Choice 4: CuF₂ + I₂

Once more, being I less active than F, the former will not displace the latter, and the reaction will not proceed.

You might be interested in

Calculate the hydroxide ion concentration [oh-] for human urine (ph = 6.2). notice this is about hydroxide.

igomit [66]

[OH⁻] = 1.6 × 10⁻⁸ mol / dm³

<h3>Explanation</h3>

By definition, $[\text{H}^{+}] = 10^{-\text{pH}}$ , where $[\text{H}^{+}]$ is the concentration of proton in the solution.

pH = 6.2 for this solution. As a result, $[\text{H}^{+} = 10^{-6.2} = 6.31 \times 10^{-7} \; \text{mol} \cdot \text{dm}^{-3}$ .

$[\text{H}^{+}] \cdot [\text{OH}^{-}] = \text{K}_w$ , where $[\text{OH}^{-}]$ the concentration of hydroxide ions and $\text{K}_w$ is the dissociation constant of water.

$\text{K}_w = 10^{-14} \; \text{mol}\cdot \text{dm}^{-3}$ at 0.10 MPa and 25 °C. As a result, $[\text{OH}^{-}] = \text{K}_w / [\text{H}^{+}] = 10^{14} / (6.31 \times 10^{-7}) = 1.6 \times 10^{-8} \; \text{mol}\cdot \text{dm}^{-3}$ .

5 0

2 years ago

If 350.0 grams of Cr2O3 are reacted with 235.0 grams of elemental silicon, 213.2 grams of chromium metal are recovered. What is

bulgar [2K]

We calculate for the amount of chromium metal in the reactant by,
= 350 x (mass of Cr2/mass of Cr2O3)
= 350 x (104/152)
= 239.47 grams
The amount of Cr metal in the product is only 213.2 grams. Thus, the percent yield.
percent yield = (213.2 grams/239.47) x 100%
= 89%

4 0

2 years ago

. A mixture of methane and air is capable of being ignited only if the mole percent of methane is between 5% and 15%. A mixture

postnew [5]

Answer:

A) Mass flow rate of air = 22.892 kmol/hr

B)percentage by mass of oxygen in the product gas = 22.52%

Explanation:

We are given that the mixture containing 9.0 mole% methane in air flowing.

Thus, we have 0.09 mole of methane(CH4) and the remaining will be the air which is (100% - 9%) = 91% = 0.91

Molar mass of CH4 = 12 + 1(4) = 16 g/mol

We are given the average molecular weight of air = 29 g/mol

Thus;

Average molar mass of air and methane mixture is;

M_avg = (0.09 × 16) + (0.91 × 29)

M_avg = 27.83 g/mol

We are told that air flowing at a rate of 7 × 10² kg/h = 700 kg/h

Thus;

Mass flow rate of CH4 in air mixture = 700kg/h × (0.09CH4)/1 mix × (1/27.83kg/kmol) = 2.264 kmol/hr

Mass flow rate of air in mixture = 2.264kmol/h × 0.91kmol air/0.09kmolCH4 = 22.892 kmol/hr

We are told that the mixture is capable of being ignited if the mole percent of methane is between 5% and 15%.

Thus, for 5% of methane, the air required will be;

2.264kmol/h × 0.95kmol air/0.05kmol CH4 = 43.016 kmol/hr

Now, the dilution air needed will be =

43.016 - 22.892 = 20.124 kmol/hr

Total mass flow rate of mixture =

700kg/hr + (20.124kmol/hr × 29kg/mol) = 1283.596 kg/hr

We are told that air consist of 21 mole% Oxygen (O2).

Molar mass of oxygen = 32

Thus;

Mass fraction of oxygen in the product gas = 43.016kmol/h × (0.21molO2/1mol air) × (32kg oxygen/1kmol oxygen) × (1/1283.596kg/h) = 0.2252

Thus, written in percentage form, we have; 22.52%

So, percentage by mass of oxygen in the product gas = 22.52%

3 0

2 years ago

Which term names the metamorphic change to a rock that results mainly from the heat energy of nearby magma? A. local metamorphis

marshall27 [118]

The answer to this question would be: <span>thermal metamorphism
</span>
Metamorphism is a change in the mineral texture without causing the rock to become liquid/magma. In this case, the metamorphic change to the rock is caused by the heat energy or thermal energy of the magma. This kind of mechanism is also called contact mechanism as the thermal energy is transferred by contact so this question option is a bit ambiguous.

8 0

2 years ago

Read 2 more answers

A student wants to draw a model of an atom. Which statement describes how to find the number of neutrons to include in the model

san4es73 [151]

c is the correct answer

4 0

2 years ago