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Alexeev081 [22]
2 years ago
10

covers a wide variety of applications such as web and computer-based training (CBT), and social networks. a. E-learning b. Model

ing c. Videodisc instruction d. Vestibule instruction
Computers and Technology
1 answer:
mixer [17]2 years ago
6 0

Answer:

Option (a) is the correct answer of this question.

Explanation:

E-Learning means that Electronic Learning. It covers a broad spectrum of applications, including online and computer-based training (CBT) and public networks.E-Learning is learning to use new technology to navigate curricula beyond a conventional classroom is known as Electronic learning.

  • E-learning is a nurturing environment that allows use of information and communication technologies (ICTs) as a pedagogical tool.
  • E-learning not a program distributed over a Disc or CD-ROM, a video tape or a TV channel.

<u>There are two types of E-learning are known as</u>:-

  1. Synchronous E-learning.
  2. Asynchronous E-learning

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Give at least one example computer application for which a connection-oriented service is appropriate and at least one example c
Leni [432]
Apple devices would be one
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2 years ago
#You may modify the lines of code above, but don't move them! #When you Submit your code, we'll change these lines to #assign di
Musya8 [376]

Answer:

The solution code is written in Python:

  1. mystery_string = "Programming"
  2. output = ""
  3. for x in mystery_string:
  4.    output += x  
  5.    print(output)

Explanation:

Firstly, create a variable mystery_string to hold a random string (Line 1).

Create an output variable to hold an output string (Line 2).

Create a for-loop to traverse the mystery_string character by character (Line 4). In the iteration, get a character from the mystery_string, and concatenate it with output string (Line 5). Print the output string (Line 6) before proceed to the next iteration.

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2 years ago
What is the distance rn between the point of application of n⃗ and the axis of rotation? what is the distance rw between the poi
Mandarinka [93]

Complete Question.

A. Suppose that you are holding a pencil balanced on its point. If you release the pencil and it begins to fall, what will be the angular acceleration when it has an angle of 10.0 degrees from the vertical?

B. What is the distance rn between the point of application of n⃗ and the axis of rotation?

C. What is the distance rw between the point of application of w⃗ and the axis? enter your answers in meters separated by a comma?

Answer:

A. â = - 17rad/s²

B. rn = 0, meters

C. rw = 0.074, meters

Explanation:

Where;

l = length of the pencil

θ = angle between the vertical line and the pencil

â = angular acceleration.

The torque due to weight about the pivotal point is negative since it's clockwise;

t = - mg(l/2)sinØ ..... equation 1

torque with respect to angular acceleration;

t = Iâ ..... equation 2

The moment of Inertia of the pencil about one end;

I = (ml²)/3

Substituting I into equation 2;

t = [(ml²)/3]×â

Equating the equation, we have;

[(ml²)/3]×â = - mg(l/2)sinØ

â = (-3gsinØ)/2l

â = (-3*9.8*sin10°)/(2*0.15)

Angular acceleration, â = -17rad/s²

B. The normal force is acting at the normal force only, so the distance r n between the point of application of n ⃗ and the axis of rotation is zero because the axis of pencil is passing the same point of application w.

C. rn = (lcosØ)/2

rn = (0.15 * cos10°)/2

rn = (0.15 * 0.9848)/2

rn = (0.1477)/2

rn = 0.074m.

Since the gravity acts at exactly half of the length of pencil, distance r w between the point of application of w⃗ and the axis equals 0.074m.

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2 years ago
Redo Programming Exercise 16 of Chapter 4 so that all the named constants are defined in a namespace royaltyRates. PLEASE DONT F
Komok [63]

Answer:

Code is given below and output is attached in the diagram:

Explanation:

//Use this header file while using visual studio.

#include "stdafx.h"

//Include the required header files.

#include<iostream>

//Use the standard naming convention.

using namespace std;

//Define a namespace royaltyRates.

namespace royaltyRates

{

    //Declare and initialize required named constants.

    const double PAY_ON_DELIVERY_OF_NOVAL = 5000;

    const double PAY_ON_PUBLISH_OF_NOVAL = 20000;

    const double PER_ON_NET_PRICE_SECOND_OPTION =

    0.125;

    const double PER_ON_NET_PRICE_FIRST_4000 = 0.1;

    const double PER_ON_NET_PRICE_OVER_4000 = 0.14;

};

//Start the execution of main() method.

int main()

{

    //Declare and initialize the required variables

    //which are going to be used to calculate

    //royalities under each option.

    float net_price;

    int num_copies;

    float royaltyUnderOption1, royaltyUnderOption2,

    royaltyUnderOption3;

    royaltyUnderOption1 = royaltyUnderOption2

    = royaltyUnderOption3 = 0;

    //Prompt the user to enter the net price of each

    //novel.

    cout << "Please enter the net price for each ";

    cout << "copy of the novel : ";

    cin >> net_price;

    //Prompt the user to enter the estimated number

    //of copies of the novels to be sold.

    cout << "Please enter the estimated number ";

    cout << "of copies to be sold : ";

    cin >> num_copies;

    //Display the required details and royalty

    //calculated under option 1.

    cout << "\n*** Option 1: ****" << endl;

    cout << "Net price of each novel: $" << net_price;

    cout << endl;

    cout << "Estimated number of copies to be sold ";

    cout << "is: " << num_copies << endl;

    cout << "$";

    cout << royaltyRates::PAY_ON_DELIVERY_OF_NOVAL;

    cout << " is paid to author for the delivery of ";

    cout << "the final manuscript and $";

    cout << royaltyRates::PAY_ON_PUBLISH_OF_NOVAL;

    cout << " is paid for the publication of ";

    cout << "novel." << endl;

    royaltyUnderOption1 =

    royaltyRates::PAY_ON_DELIVERY_OF_NOVAL +

    royaltyRates::PAY_ON_PUBLISH_OF_NOVAL;

    cout << "Total amount of royalty under option 1 ";

    cout << "is $" << royaltyUnderOption1 << endl;

    //Display the required details and royalty

    //calculated under option 2.

    cout << "\n*** Option 2: ****" << endl;

    cout << "Net price of each novel: $";

    cout << net_price << endl;

    cout << "Estimated number of copies to be sold ";

    cout << "is: " << num_copies << endl;

    royaltyUnderOption2 =

   (royaltyRates::PER_ON_NET_PRICE_SECOND_OPTION *

    net_price)* num_copies;

    cout << "Total amount of royalty under option 2 ";

    cout << "is $" << royaltyUnderOption2 << endl;

    //Display the required details and royalty

    //calculated under option 3.

    cout << "\n*** Option 3: ****" << endl;

    cout << "Net price of each novel: $" << net_price;

    cout << endl;

    cout << "Estimated number of copies to be sold ";

    cout << "is: " << num_copies << endl;

    //If the number of copies is greater than 4000.

    if (num_copies > 4000)

    {

         //Total amount of royalty will be 10% of net

         //price of first 4000 copies and 14 % of net

         //price of copies sold over 4000.

         royaltyUnderOption3 =

         (royaltyRates::PER_ON_NET_PRICE_FIRST_4000 *

         net_price) * 4000 +

         (royaltyRates::PER_ON_NET_PRICE_OVER_4000 *

         net_price) * (num_copies - 4000);

    }

    //Otherwise,

    else

    {

         //Total amount of royalty will be 10% of net

         //price of first 4000 copies.

         royaltyUnderOption3 =

         (royaltyRates::PER_ON_NET_PRICE_FIRST_4000 *

         net_price) * num_copies;

    }

    cout << "Total amount of royalty under option 3 ";

    cout << "is $" << royaltyUnderOption3 << endl;

    //If the royalty under option 1 is greater than

    //royalty under option 2 and 3, then option 1 is

    //best option.

    if (royaltyUnderOption1 > royaltyUnderOption2 &&

    royaltyUnderOption1 > royaltyUnderOption3)

    {

         cout << "\nOption 1 is the best option that ";

         cout << "author can choose." << endl;

    }

    //If the royalty under option 2 is greater than

    //royalty under option 1 and 3, then option 2 is

    //best option.

    else if (royaltyUnderOption2 > royaltyUnderOption1

    && royaltyUnderOption2 > royaltyUnderOption3)

    {

         cout << "\nOption 2 is the best option that ";

         cout << "author can choose." << endl;

    }

    //If the royalty under option 3 is greater than

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    //best option.

    else

    {

         cout << "\nOption 3 is the best option that ";

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    system("pause");

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}

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An intruder with malicious intent breaks into an office and steals a hard drive containing sensitive information about the compa
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Answer:

firewalls and encryption

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