Question

Given an integer representing a 10-digit phone number, output the area code, prefix, and line number using the format (800) 555-1212. Ex: If the input is: 8005551212 the output is: (800) 555-1212 Hint: Use % to get the desired rightmost digits. Ex: The rightmost 2 digits of 572 is gotten by 572 % 100, which is 72. Hint: Use // to shift right by the desired amount. Ex: Shifting 572 right by 2 digits is done by 572 // 100, which yields 5. (Recall integer division discards the fraction). For simplicity, assume any part starts with a non-zero digit. So 0119998888 is not allowed.

Answer 1

Given an integer representing a 10-digit phone number, output the area code, prefix, and line number using the format (800) 555-1212.

The examples and taken into account and the code is written.

The code for the above statement is given below :

Explanation:

phone_number = input()

if (len(phone_number)==10):

print(phone_number[0] + phone_number[1] + phone_number[2] + '-' + phone_number[3] + phone_number[4] + phone_number[ 5] + '-' + phone_number[6] + phone_number[7] + phone_number[8] + phone_number[9])

else:

print('invalid phone number')

The number is taken as the input. Then, the length is checked.

If the number starts with 0 it is not allowed.

Answer 2

Answer:

input: 8005551212

phone_number = int(input())

area_code = phone_number // 10000000

prefix = (phone_number // 10000) % 1000

line_number = phone_number % 10000

print(f'({area_code}) {prefix}-{line_number}')

Explanation:

#input data

8005551212

#define phone number to input data

phone_number = int(input())

#logic to find area_code, prefix, and line_number

area_code = phone_number // 10000000

prefix = (phone_number // 10000) % 1000

line_number = phone_number % 10000

#f-strings(format strings) are a shorter way of doing str.format() calls.

print(f'({area_code}) {prefix}-{line_number}')