Question

A scientist is measuring the temperature change in a chemical compound. The temperature dropped 11F per hour from the original temperature. After 4 hours, the temperature was 90 F. Find the compound's original temperature.

Answer 1

Answer:

134F

Step-by-step explanation:

Let C represent temperature and t represent number of hours.

We have been given that the temperature dropped 11 F per hour from the original temperature. So temperature dropped in t hours would be $-11t$.

We will represent our given equation in slope-intercept form:

$C=-11t+b$, where b is initial temperature of compound.

We have been given that after 4 hours, the temperature was 90 F. This means point $(4,90)$ in on the line. So we will get:

$90=-11(4)+b$

$90=-44+b$

$90+44=-44+44+b$

$134=b$

Therefore, the original temperature of the compound is 134F.