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2 years ago

5

Patty has a flower box in the shape of a rectangular prism with interior dimensions that are 15 inches in length, 8 inches in wi

dth, and 6 inches in height. Patty will fill the flower box 3 fourths full of soil. How many cubic inches of soil will be in the flower box?

1 answer:

devlian [24]2 years ago

7 0

Answer:

Step-by-step explanation:

V=1/2lbh

V=1/2×15×8×6

V=360inches

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A rectangle has a length that is equal to 4 less than twice the width. The function for the perimeter depending on the width can

Lady_Fox [76]

Answer:

The mathematical domain includes all real numbers, while the reasonable domain includes only real numbers greater than 2

Step-by-step explanation:

In the real world, length and width only make sense when they are positive. For that to be the case, the width must be greater than 2. There is nothing in the description that restricts the values to integers.

8 0

2 years ago

A contractor has submitted bids on three state jobs: an office building, a theater, and a parking garage. State rules do not all

german

Answer:

The following are the answer to this question:

Step-by-step explanation:

In the given question the numeric value is missing which is defined in the attached file please fine it.

Calculating the probability of the distribution for x:

$\to f(x) = 0.19\ for \ x=14\\\\\to f(x) = 0.29 \ for\ x=7\\\\\to f(x) = 0.38\ for \ x=1\\\\\to f(x)=0.14 \ for \ x=0\\$

The formula for calculating the mean value:

$\bold{ E(X)= x \times f(x)}$

$=14 \times 0.19+7 \times 0.29+1 \times 0.38+0\times 0.14\\\\=2.66 + 2.03+0.38+ 0\\\\=5.07$

$\bold{E(X^2) = x^2 \times f(x)}$

$=14^2 \times 0.19+7^2 \times 0.29+1^2 \times 0.38+0^2 \times 0.14 \\\\=196 \times 0.19+ 49 \times 0.29+1 \times 0.38+0 \times 0.14\\\\= 37.24+ 14.21+ 0.38+0 \\\\=51.83$

use formula for calculating the Variance:

$\to \bold{\text{Variance}= E(X^2) -[E(X)]^2}$

$= 51.83 - (5.07)^2\\\\= 51.83 - 25.70\\\\=26.13$

calculating the value of standard deivation:

Standard Deivation (SD) = $\sqrt{Variance}$

$= \sqrt{26.13} \\\\=5.111$

6 0

2 years ago

Shania is making a scale diagram of the badminton court at the community center. She uses a scale of 1 centimeter to 0.5 meter t

docker41 [41]

1m = 100cm

1cm → 0.5m

1cm → 0.5 · 100cm = 50cm

The scale: $\dfrac{50}{1}=50$

length = 26.8cm · 50 = 1,340cm = 13.40m

width = 12.2cm · 50 = 610cm = 6.10m

The area of the court:

A = 13.40 · 6.10 = 81.74 m²

8 0

2 years ago

The graph shows the solution to the initial value problem y'(t)=mt, y(t0)= -4

Charra [1.4K]

$y'(t)=mt
\\
\\ y=\int {mt} \, dt=m \int{t} \,dt=m \frac{t^2}{2} +C \\ \\y= \frac{mt^2}{2}+C$

Now find equation of the graph. It passes through the point (2,3), and intersects y-axis at -2.

$y=at^2+b
\\
\\3=a\times 2^2-2
\\
\\3=4a-2
\\
\\5=4a
\\
\\a= \frac{5}{4} 
\\
\\y=\frac{5}{4} t^2-2 \\ \\y= \frac{m}{2} t^2+C
\\ \\ \frac{m}{2} = \frac{5}{4} 
\\
\\m= \frac{5}{2} 
\\
\\C=-2
\\
\\y(t_0)=-4
\\
\\-4= \frac{5}{4} t_0^2-2
\\
\\ -2= \frac{5}{4} t_0^2
\\
\\ t_0^2=- \frac{8}{5} 
\\
\\t_0=\pm \sqrt{- \frac{8}{5} }$

3 0

2 years ago

For making a scatter plot of the data set, which would be the best scale and interval for the axis that represents the amount of

Serga [27]

I'd say the answer to the first question is D) 0 to 4 with intervals of 0.2.

Because, you can't just have 1 to 4, as some of the numbers are less than 1. Of course you can't have 2 to 5 either. And intervals of 2 would be too messy.

For the second question:

I believe the answer is A. Because it's obvious that there IS one outlier, and it looks like there are two clusters.

So, the answers are: A) and D).

8 0

2 years ago