answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
larisa [96]
2 years ago
5

A single Na /K ATPase pump is present in the plasma membrane of an artificial cell with an initial cellular environment of 1000

molecules of Na and 1000 molecules of ATP inside the cell, 1000 molecules of K outside the cell, and a net charge differential across the plasma membrane of 0. Assuming the only changes in the cellular environment are a result of the pump's actions, what would be the number of Na , K and ATP molecules inside the cell after 100 cycles of the pump and what would be the net charge differential (inside - outside) across the plasma membrane?
Biology
2 answers:
Evgen [1.6K]2 years ago
3 0

Answer:

The correct answer is: there will be 700 Na+ molecules, 200 K+ molecules, 900 ATP molecules, and a net charge differential of -200.

Explanation:

Inside the cell, there's 1000 molecules of Na+ and 1000 molecules of ATP.

Outside the cell, there's 1000 molecules of K+.

The Na+/K+ ATPase expels 3 molecules of Na+ and enters 2 molecules of K+ with every pump.

If there's only one Na/K ATPase and there are not other changes in the cellular environment, and the Na/K ATPase pumps 100 times, we can assume that 300 molecules of Na+ will exit the cell, and 200 molecules of K+ will enter the cell. Every pump costs 1 ATP molecule, so there will be 100 ATP molecules used.

"what would be the number of Na , K and ATP molecules inside the cell after 100 cycles of the pump and what would be the net charge differential (inside - outside) across the plasma membrane?"

Na+ inside the cell: 1000 - 300 = 700 Na+ molecules.

K+ inside the cell: 200 K+ molecules.

ATP inside the cell: 1000 - 100 = 900 ATP molecules.

Net charge differential: -200

vivado [14]2 years ago
3 0

Answer / Explanation:

To properly understand this question, let us first try to understand what an Na+ K+ pump is:

The Na+ K+ pump is an electro-genic transmembrane ATPase. Situated in the outer plasma membrane of the cells; on the cytosolic side.

We need to also know that the plasma membrane is a lipid bilayer arranged asymmetrically and contains cholesterol, phospholipids, glycolipids, sphingolipid, and proteins within the membrane. Part of the function of the Na+K+ -ATPase pump is to helps maintain osmotic equilibrium and membrane potential in cells.

With the understanding of the above, if we go further to solving the question, we have:

700 Na+; 200 K+; 900 ATP and -200 charge differential (inside - outside).

So for further explanation,

We can say that:

For the Inside cells, there are 1000 molecules of Na+ and 1000 molecules of ATP.

For the Outside cells, there's 1000 molecules of K+.

The Na+/K+ ATPase dismisses 3 molecules of Na+ and enters 2 molecules of K+ with every pump.

Therefore, If there's only one Na/K ATPase and there is no changes in the cellular environment,

Hence, the Na/K ATPase pumps 100 times.

So we can suggest that 300 molecules of Na+ will leave the cell, and 200 molecules of K+ will enter the cell.

Every pump costs 1 ATP molecule, so there will be 100 ATP molecules used.

Therefore, we can conclude that:

700 Na+; 200 K+; 900 ATP and -200 charge differential (inside - outside) which represent or equates to the answer we are looking for.

You might be interested in
Suppose the sub-hypothesis that wing waving alone reduces predation by jumping spiders was supported by the Zonosemata experimen
Sliva [168]

Answer:

The correct answer is: <em>Zonosemata flies with housefly wings are attacked less frequently</em>

Explanation:

The Zonosemata experiment is a scientific experiment that was conducted to investigate how zonosemata flies are able to protect themselves from predation by jumping spiders. In this study, housefly wings were transplanted onto zonosemata flies. This made zonosemata flies protected from attack by jumping spiders. On the other hand, when zonosemata wings were transplanted onto houseflies, they were easy targets for jumping spiders. Therefore, if the sub-hypothesis that wing waving alone reduces predation by jumping spiders is proven, the logical result would be that:  Zonosemata flies with housefly wings are attacked less frequently.

4 0
2 years ago
Which of these choices is a disadvantage of the endangered species act ?
Mazyrski [523]
A.<span>Can be difficult to increase wild populations </span>
3 0
2 years ago
Read 2 more answers
You know that the narrow-sense heritability of milk production in Ayrshire cattle is 0.587. You perform an experiment where you
Paha777 [63]

Answer:

Explanation:

Narrow sense heritability - h​​​​2

​​​​​​selection differential - S

Selection differential is calculated from the difference between the population average and the parental population.

Breeder's equation:

Response to selection - R = h​​​​​​2S

Mean milk production of 10% cows for experiment = 8.9L/hr

Mean milk production of parental population = 5.1L/hr

Selection differential S= 8.9 - 5.1 = 3.8 L/hr

Response to selection = 0.587 × 3.8 = 2.23

3 0
2 years ago
Organism A and organism B are both classified in the same phylum. Which additional information about the two species can be conc
Sedbober [7]
The correct answer is C
4 0
2 years ago
In certain bacteria, an oval shape (O) is dominant over round (o) and thick cell walls (T) are dominant over thin (t). Draw on a
seropon [69]

Answer:

Consider the heterozygous oval, thick cell walled bacteria to have the alleles OoTT and the thin cell walled bacteria to have alleles oott. Results will be 50% oval, thick walled bacteria and 50% round, thick walled bacteria. This will be the F1 progeny.

When the oval, thick walled bacteria from the F1 progeny is cross bred with round, thick walled bacteria then 25 percent of the bacteria will be heterozygous oval, thick walled. 25 percent will be heterozygous oval and heterozygous thick walled. 25 percent will be round and thick walled. 25 percent will be round and thin walled.

6 0
2 years ago
Other questions:
  • How do small intestinal epithelial and root hair cells function in nutrient procurement?
    15·1 answer
  • Viruses are made up of either DNA or RNA surrounded by a coating of protein. when the two main substances that make up a virus a
    10·2 answers
  • Why are telomeres a necessary component of linear chromosomes? they maintain the length of a chromosome because dna is shortened
    5·1 answer
  • Rewrite the following sentence to make it true.<br><br>Geologists subdivide periods into eras​
    11·1 answer
  • Imagine that you work at the medical examiner's office for a major metropolitan city. As Chief Medical officer, you investigate
    10·1 answer
  • Compare and contrast light microscopes, scanning electron microscopes, and transmission electron microscopes. Sort each statemen
    11·1 answer
  • Students at a university were split into two groups and each received a different text for a philosophy course. One group receiv
    7·1 answer
  • Initial number of finches
    15·1 answer
  • The receptive field of this type of cell in the striate cortex is made up of a large number of receptive fields from neurons in
    15·1 answer
  • Observable matter makes up about what percentage of the universe?<br> 5%<br> 12%<br> 50%<br> 95%
    10·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!