0.37
0.194
0.6
0.473
0.29
the smallest digit at tenth place is 1 in 0.194, so 0.194 is the smallest here
The given points are
R=(8,-2) , S=(11,-6), O=(-3,-9), and P=(0,-13)
To find the value of u and v, we have to perform subtraction of the points . That is


Since we get the same values of u and v , therefore the two vectors are equal .
First of all, a bit of theory: since the area of a square is given by

where s is the length of the square. So, if we invert this function we have
.
Moreover, the diagonal of a square cuts the square in two isosceles right triangles, whose legs are the sides, so the diagonal is the hypothenuse and it can be found by

So, the diagonal is the side length, multiplied by the square root of 2.
With that being said, your function could be something like this:
double diagonalFromArea(double area) {
double side = Math.sqrt(area);
double diagonal = side * Math.sqrt(2);
return diagonal;
}
A dilation is a transformation

, with center O and a scale factor of k that is not zero, that maps O to itself and any other point P to P'.
The center O is a fixed point, P' is the image of P, points O, P and P' are on the same line.
In a dilation of

, the scale factor,

is mapping the original figure to the image in such a way that the
distances from O to the vertices of the image are half the distances
from O to the original figure. Also the size of the image is half the
size of the original figure.
Therefore, <span>If

is a dilation of △ABC, the truth about the image △A'B'C'</span> are:
<span>AB is parallel to A'B'.

The distance from A' to the origin is half the distance from A to the origin.</span>