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IRINA_888 [86]
2 years ago
7

Irwin rode his bicycle from one end of a trail to another and back at a speed of 20 miles per hour. If the trail is 4 miles long

, for how many hours was Irwin riding?
A.0.2 hours

B.0.4 hours

C.2.5 hours

D.5.0 hours
Mathematics
1 answer:
ladessa [460]2 years ago
6 0

Answer:the answer is C yw :)

Step-by-step explanation:

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What is the area of the shaded region?
azamat

Answer:

(25\pi\ -24)\ cm^{2}

Step-by-step explanation:

we know that

The area of the shaded region is equal to the area of the circle minus the area of the two isosceles triangles

so

Find the area of the circle

The area of the circle is equal to

A=\pi r^{2}

where r is the radius of the circle

In this problem we have

r=5\ cm

substitute

A=\pi (5)^{2}

A1=25\pi\ cm^{2}

Find the area of the two triangles

The area of the two isosceles triangles is equal to

A=2[\frac{1}{2}bh]=bh

we have

b=6\ cm

h=5-1=4\ cm

substitute

A2=6*4=24\ cm^{2}

Find the area of the shaded region

A1-A2=(25\pi\ -24)\ cm^{2}

5 0
2 years ago
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Please help I don't understand this problem. I need to get this done by tonight.
Lapatulllka [165]

Answer:

Step-by-step explanation:

24

4 0
2 years ago
A supermarket has two customers waiting to pay for their purchases at counter I and one customer waiting to pay at counter II. L
Pachacha [2.7K]

Answer:

b. 0.864

Step-by-step explanation:

Let's start defining the random variables.

Y1 : ''Number of customers who spend more than $50 on groceries at counter 1''

Y2 : ''Number of customers who spend more than $50 on groceries at counter 2''

If X is a binomial random variable, the probability function for X is :

P(X=x)=(nCx)p^{x}(1-p)^{n-x}

Where P(X=x) is the probability of the random variable X to assume the value x

nCx is the combinatorial number define as :

nCx=\frac{n!}{x!(n-x)!}

n is the number of independent Bernoulli experiments taking place

And p is the success probability.

In counter I :

Y1 ~ Bi (n,p)

Y1 ~ Bi(2,0.2)

P(Y1=y1)=(2Cy1)(0.2)^{y1}(0.8)^{2-y1}

With y1 ∈ {0,1,2}

And P( Y1 = y1 ) = 0 with y1 ∉ {0,1,2}

In counter II :

Y2 ~ Bi (n,p)

Y2 ~ Bi (1,0.3)

P(Y2=y2)=(1Cy2)(0.3)^{y2}(0.7)^{1-y2}

With y2 ∈ {0,1}

And P( Y2 = y2 ) = 0 with y2 ∉ {0,1}

(1Cy2) with y2 = 0 and y2 = 1 is equal to 1 so the probability function for Y2 is :

P(Y2=y2)=(0.3)^{y2}(0.7)^{1-y2}

Y1 and Y2 are independent so the joint probability distribution is the product of the Y1 probability function and the Y2 probability function.

P(Y1=y1,Y2=y2)=P(Y1=y1).P(Y2=y2)

P(Y1=y1,Y2=y2)=(2Cy1)(0.2)^{y1}(0.8)^{2-y1}(0.3)^{y2}(0.7)^{1-y2}

With y1 ∈ {0,1,2} and y2 ∈ {0,1}

P( Y1 = y1 , Y2 = y2) = 0 when y1 ∉ {0,1,2} or y2 ∉ {0,1}

b. Not more than one of three customers will spend more than $50 can mathematically be expressed as :

Y1 + Y2 \leq 1

Y1 + Y2\leq 1 when Y1 = 0 and Y2 = 0 , when Y1 = 1 and Y2 = 0 and finally when Y1 = 0 and Y2 = 1

To calculate P(Y1+Y2\leq 1) we must sume all the probabilities that satisfy the equation :

P(Y1+Y2\leq 1)=P(Y1=0,Y2=0)+P(Y1=1,Y2=0)+P(Y1=0,Y2=1)

P(Y1=0,Y2=0)=(2C0)(0.2)^{0}(0.8)^{2-0}(0.3)^{0}(0.7)^{1-0}=(0.8)^{2}(0.7)=0.448

P(Y1=1,Y2=0)=(2C1)(0.2)^{1}(0.8)^{2-1}(0.3)^{0}(0.7)^{1-0}=2(0.2)(0.8)(0.7)=0.224

P(Y1=0,Y2=1)=(2C0)(0.2)^{0}(0.8)^{2-0}(0.3)^{1}(0.7)^{1-1}=(0.8)^{2}(0.3)=0.192

P(Y1+Y2\leq 1)=0.448+0.224+0.192=0.864\\P(Y1+Y2\leq 1)=0.864

7 0
2 years ago
On a coordinate plane, 5 trapezoids are shown. Trapezoid L M N P is in quadrant 2 and has points (negative 5, 1), (negative 5, 4
Law Incorporation [45]

Answer:

The answer is figure C

Step-by-step explanation:

Just did it 2020

5 0
2 years ago
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The keyless entry system in some cars uses a 4-digit keypad. There are 10 possible digits, and the digits can be repeated. How m
Len [333]
This item can be answered through the concept of fundamental principles of counting. In the first of the four digits, there are 10 possible digits. The same with all the other 3 places or digits of the code. That is,
                             n = 10 x 10 x 10 x 10 
Giving us the answer of 10,000. Thus, there are 10,000 possible keys for the keyless entry. 
8 0
2 years ago
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