Question

Which shows one way to determine the factors of x3 – 12x2 – 2x + 24 by grouping? plzzzzz answerr x(x2 – 12) + 2(x2 – 12) x(x2 – 12) – 2(x2 – 12) x2(x – 12) + 2(x – 12) x2(x – 12) – 2(x – 12)

Answer 1

Answer:

Step-by-step explanation:

The idea of factoring by grouping is that you don't move anything around.  You leave the polynomial in descending order of powers of x and group them together in groups of 2.

$(x^3-12x^2)-(2x+24)=0$

Then you factor out what is common in each set of parenthesis.

$x^2(x-12)-2(x-12)$

You know if factoring by grouping "works" if what's inside both sets of parenthesis is exactly the same.  Both of ours are (x - 12), so grouping "worked".  Match the factoring above to one of your answers.