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2 years ago

Which equation has x = –6 as the solution?

Mathematics

2 answers:

olya-2409 [2.1K]2 years ago

3 0

Answer:

The equation 'log Subscript 3 Baseline (negative 2 x minus 3) = 2' i.e. $\log _3\left(-2x-3\right)=2$ has x = –6 as the solution.

Step-by-step explanation:

<u>Checking the equation</u>

log Subscript 3 Baseline (negative 2 x minus 3) = 2

Writing in algebraic expression

$\log _3\left(-2x-3\right)=2$

Use the logarithmic definition

$\mathrm{If}\:\log _a\left(b\right)=c\:\mathrm{then}\:b=a^c$

$\log _3\left(-2x-3\right)=2\quad \Rightarrow \quad \:-2x-3=3^2$

$-2x-3=3^2$

$-2x-3=9$

$-2x=12$

$\mathrm{Divide\:both\:sides\:by\:}-2$

$\frac{-2x}{-2}=\frac{12}{-2}$

$x=-6$

Therefore, the equation 'log Subscript 3 Baseline (negative 2 x minus 3) = 2' i.e. $\log _3\left(-2x-3\right)=2$ has x = –6 as the solution.

KonstantinChe [14]2 years ago

3 0

Answer:

(-2x-3)=2

Step-by-step explanation:

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Set up a proportion for these problems. For the first question,
340/1 = 30/x

Cross multiply:
340*x = 1*30
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Divide both sides by 340:
340x/340=30/340
x = 30/340 = 3/34

For the second question,
340/1 = 150/x

Cross multiply:
340*x = 150*1
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Divide both sides by 340:
340x/340 = 150/340
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