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IrinaVladis [17]
2 years ago
5

Which equation has x = –6 as the solution?

Mathematics
2 answers:
olya-2409 [2.1K]2 years ago
3 0

Answer:

The equation 'log Subscript 3 Baseline (negative 2 x minus 3) = 2' i.e. \log _3\left(-2x-3\right)=2  has x = –6 as the solution.

Step-by-step explanation:

<u>Checking the equation</u>

log Subscript 3 Baseline (negative 2 x minus 3) = 2

Writing in algebraic expression

\log _3\left(-2x-3\right)=2

Use the logarithmic definition

\mathrm{If}\:\log _a\left(b\right)=c\:\mathrm{then}\:b=a^c

\log _3\left(-2x-3\right)=2\quad \Rightarrow \quad \:-2x-3=3^2

-2x-3=3^2

-2x-3=9

-2x=12

\mathrm{Divide\:both\:sides\:by\:}-2

\frac{-2x}{-2}=\frac{12}{-2}

x=-6

Therefore, the equation 'log Subscript 3 Baseline (negative 2 x minus 3) = 2' i.e. \log _3\left(-2x-3\right)=2  has x = –6 as the solution.

KonstantinChe [14]2 years ago
3 0

Answer:

(-2x-3)=2

Step-by-step explanation:

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a) Failed to reject the null hypothesis (P-value=0.09).

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Step-by-step explanation:

a) We have to perform a hypothesis test for the difference of proportions.

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The significance level is 0.05.

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The estimated standard deviation is

s=\sqrt{\frac{p(1-p)}{n_1}+\frac{p(1-p)}{n_2}} =\sqrt{\frac{0.1153(1-0.1153)}{2142}+\frac{0.1153(1-0.1153)}{399}} =0.0174

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The z-value for this CI is 1.96.

We have to recalculate the standard deviation:

\sigma=\sqrt{\frac{p_1(1-p_1)}{n_1} +\frac{p_2(1-p_2)}{n_2}} =\sqrt{\frac{0.1116(1-0.1116)}{2142} +\frac{0.1353(1-0.1353)}{399}} =0.0184

The lower limit is then:

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The upper limit is:

UL=(p_1-p_2)+z*\sigma=(0.1116-0.1353)+1.96*0.0184=-0.0238+0.0361\\\\UL=0.0124

The 95% CI for the difference in proportions is:

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