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Leokris [45]
2 years ago
6

Select one or more of the following: Which of these events will cause signal(s) to be generated by the kernel (the operating sys

tem itself) and sent to your childless foreground process?
a. The process has done something wrong (segmentation fault, etc.)
b. A timer has expired, which sends the signal SIGALRM
c. The process has exited normally
Computers and Technology
1 answer:
nikitadnepr [17]2 years ago
7 0

Answer:

a. The process has done something wrong (segmentation fault, etc.)

Explanation:

Events that cause signals to be generated by kernel and sent to childless foreground process is the process has done something wrong(segmentation fault), as Hardware exceptions generate signals,for example, divide by 0 or invalid memory reference. These conditions are usually detected by the hardware, and the kernel is notified. The kernel then generates the appropriate signal for the process that was running at the time the condition occurred.

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Give a proof for each statement.
Marrrta [24]

Answer:

  • If a group of 9 kids have won a total of 100 trophies, then at least one of the 9 kids has won at least 12 trophies.
  • If a person buys at least 400 cups of coffee in a year, then there is at least one day in which the person has bought at least two cups of coffee.
  • The average of three real numbers is greater than or equal to at least one of the numbers.

Explanation:

1)

Suppose that  each kid has less than 12 trophies

Total trophies = 100

Maximum trophies won by one kid = 11

total kids = 9

total number of trophies = 9 * 11 = 99 which contradicts the fact the total number of trophies are 100

2)

Suppose that  person has less than 2 cups of coffee a day

Total cups of coffee = 400

he has bought at least one cup of coffee each day

which means

total number of cups of coffee = 1* 366 = 366 which contradicts the fact the person buys at least 400 cups of coffee in a year

3)

Average of three number = (a+ b+ c)/3

suppose that there are real numbers a, b, and c such  that all three numbers are less than the average of the three numbers.

Let m be the average (a+b+c )/3 = m. Then our assumption states that (a < m) and  (b < m) and (c < m). By adding all the inequalities we get a + b + c < 3m. But m is  defined to be (a+b+c) /3  , so a + b + c = 3m.  But now we have that 3m = a + b + c < 3m. So 3m < 3m which is an obvious  contradiction. Thus our claim is true

7 0
2 years ago
A __________ error does not prevent the program from running, but causes it to produce incorrect results. a. syntax b. hardware
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Answer:

1) syntax error

2)task

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4) pseudocode

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2.32 LAB: Musical note frequencies On a piano, a key has a frequency, say f0. Each higher key (black or white) has a frequency o
Maurinko [17]

Answer:

#include<iostream>

#include<iomanip>

#include<cmath>

using namespace std;

int main()

{

float f0;

cout<<"Initial Frequency: ";

cin>>f0;

for(int n = 1; n<=5;n++)

{

 cout<<f0<<setprecision(2);

 f0 = f0 * pow(2.0,1.0/12);

 cout<<" ";

}

 

return 0;

}

Explanation:

The programming language is not stated; However, one can easily deduce that the program is to be written using C++

The following libraries enable the program to make use of some built in functions

<em>#include<iostream> </em>

<em>#include<iomanip> </em>

<em>#include<cmath> </em>

using namespace std;

int main()

{

This line declares the initial frequency as float

float f0;

This line prompts user for input

cout<<"Initial Frequency: ";

This line gets user input

cin>>f0;

The following iteration calculates and prints the frequency for thenexr 4 keys

<em>for(int n = 1; n<=5;n++) </em>

<em> { </em>

<em>  cout<<f0<<setprecision(2); </em>

<em>  f0 = f0 * pow(2.0,1.0/12); </em>

<em>  cout<<" "; </em>

<em> }  </em>

return 0;

}

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