Write the definition of a function power_to, which receives two parameters. The first is a float and the second is an integer. T
1 answer:
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Answer:
Here is the calcPrice.c program:
#include <stdio.h> //to use input output functions
int main(void) { //start of main method
int itemNo, month, day, year, quantity; //declares variables to hold item number, quantity, and date
float unitPrice; //declare variable to hold price per unit
printf("Enter item number: "); // prompts user to enter item number
scanf("%d", &itemNo); //reads item number from user and stores it in itemNo variable
printf("Enter unit price: "); // prompts user to enter unit price
scanf("%f", &unitPrice); //reads input unit price and stores it in unitPrice variable
printf("Enter quantity: "); //prompts user to enter quantity
scanf("%d", &quantity); //reads input quantity and stores it in quantity variable
printf("Enter purchase date (mm/dd/yyyy): "); //prompts user to enter purchase date
scanf("%d/%d/%d", &month, &day, &year); //reads input date and stores it in month, day and year variables
float totalAmount = unitPrice * quantity; //computes the total amount
printf("\nItem\tUnit Price\tQTY\tPurchase Date\tTotal Amount\n"); //displays the item, unit price, qty, purchase data and total amount with tab space between each
printf("%d\t$%5.2f\t%d\t%.2d/%.2d/%d\t$%5.2f\n", itemNo, unitPrice,quantity, month, day, year,totalAmount); } //displays the values of itemNo, unitPrice, quantity, month, day, year and computed totalAmount with tab space between each
Explanation:
Lets suppose user enters 583 as item number, 13.5 as unit price, 2 as quantity and 09/15/2016 as date so
itemNo = 583
unitPrice = 13.5
quantity = 2
month = 09
day = 15
year = 2016
totalAmount is computed as:
totalAmount = unitPrice * quantity;
totalAmount = 13.5* 2
totalAmount = 27.00
Hence the output of the entire program is:
Item Unit Price QTY Purchase Date Total Amount
583 $ 13.50 2 09/15/2016 $ 27.00
The screenshot of the program along with its output is attached.
Answer:
Following are the code to this question:
#include<stdio.h>//defining header file
int AND(int x,int y) //defining a method AND that hold two variable in its parameter
{
if(x==1 && y==1)//defining if block to check x and y value is equal to 1
{
return 1;//return value 1
}
else //defining else block
{
return 0;//return value 0
}
}
int OR(int x,int y)//defining method OR that hold two variable in its parameter
{
if(x==0&&y==0)//defining if block to check x and y value is equal to 1
{
return 0;//return value 0
}
else //defining else block
{
return 1;//return value 1
}
}
int main()//defining main method
{
int a,b,c;//defining integer variable
int k=1;//defining integer variable k that holds a value 1
while(k<=8)//defining while loop for 8 time input
{
printf("Please insert 3 numbers in (0 0r 1):\n ");//print message
scanf("%d%d%d", &a, &b, &c);//input value
k++;//increment the value of k by 1
printf("value: %d\n",AND(OR(a,b),c));
}
return 0;
}
Output:
please find the attachment.
Explanation:
In the above-given C language code two methods "AND and OR" is declared, holds two integer variable "x and y" in its parameters, inside the method a conditional it used that can be defined as follows:
- In the AND method, inside a conditional statement, if block check x and y both value is same that is 1 it will return 1 or it will goto else block in this it will return value 0.
- In the OR method, inside a conditional statement, if block check x and y both value is the same, that is 0 it will return 0 or it will goto else block in this it will return value 1.
- In the main method, four integers "a,b,c, and k" is declared in which variable "a, b, c" is used in the loop for 8 times input values from the user and print method is used to call the method and prints its return values.
