Answer:
The correct answer is:
a. M54.6, C79.51, C80.1
Explanation:
- M54.6 Pain in thoracic spine. It is a billable/specific ICD-10-CM code that can be used to indicate a diagnosis for reimbursement purposes. The 2020 edition of ICD-10-CM M54.
- C79.51: Secondary malignant neoplasm of bone, it is a billable/specific ICD-10-CM code that can be used to indicate a diagnosis for reimbursement purposes.
- G89. 3 is a billable/specific ICD-10-CM code that can be used to indicate a diagnosis for reimbursement purposes. The 2020 edition of ICD-10-CM G89.
Malignant neoplasm of anus, unspecified
Neoplasm related pain (acute) (chronic)
Pain in thoracic spine. M54. 6 is a billable/specific ICD-10-CM code that can be used to indicate a diagnosis for reimbursement purposes. The 2020 edition of ICD-10-CM M54.
Malignant (primary) neoplasm, unspecified
- C80. 1 is a billable/specific ICD-10-CM code that can be used to indicate a diagnosis for reimbursement purposes. The 2020 edition of ICD-10-CM C80.
Answer:
Big Oh notation is used to asymptotically bound the growth of running time above and below the constant factor.
Big Oh notation is used to describe time complexity, execution time of an algorithm.
Big Oh describes the worst case to describe time complexity.
For the equation; T(N) = 10000*N + 0.00001*N^3.
To calculate first of all discard all th constants.
And therefore; worst case is the O(N^3).
Answer:
- #include <stdio.h>
- int main()
- {
- const double piVal = 3.14159;
- double sphereVolume = 0.0;
- double sphereRadius = 0.0;
-
- sphereRadius = 1.0;
- sphereVolume = 4.0/ 3.0 * piVal * sphereRadius * sphereRadius * sphereRadius;
-
-
- printf("Sphere volume: %lf\n", sphereVolume);
- return 0;
- }
Explanation:
Firstly we can identify the formula to calculate volume of sphere which is
Volume = 4/3 
With this formula in mind, we can apply this formula to calculate the volume of sphere in Line 10. This is important to perform floating-point division 4.0/3.0 to ensure the resulting value is a floating value as well. Since we have been given piVal and sphereRadius, we can just multiply the result of floating-point division with piVal and sphereRadius and get the sphereVolume value.
At last, display the sphere volume using printf method (Line 13).
Answer:
val > max
Explanation:
Assuming the values array is already created, inside the loop, we need to check if the val, a value in the values array, is greater than max. If it is greater than the max, that means it is our new max. Then we would set the max as the val. This way, if there is any value greater than max, it will be our max at the end of the loop.
