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krok68 [10]
2 years ago
4

Consider a swapping system in which memory consists of the following hole sizes in memory order: 10 MB, 4 MB, 20 MB, 18 MB, 7 MB

, 9 MB, 12 MB, and 15 MB. Which hole is taken for successive segment requests of (a) 12 MB (b) 10 MB (c) 9 MB for first fit? Now repeat the question for best fit, worst fit, and next fit.
Computers and Technology
1 answer:
Nesterboy [21]2 years ago
7 0

Answer:

First Fit - Allocated Memory 20 MB, 10 MB, and 18 MB.

Next Fit - Allocated Memory 20 MB, 18 MB, and 9 MB.

Best Fit - Allocated Memory 12 MB, 10 MB, and 9 MB.

Worst Fit - Allocated Memory 20 MB, 10 MB, and 15 MB.

Explanation:

Memory Management Systems basically have four types - First Fit, Next Fit, Best Fit and Worst Fit. These memory systems work differently to allocate the memory in operating system.

<u>Given-</u>

We have memory sizes - 10 MB, 4 MB, 20 MB, 18 MB, 12 MB and 15 MB.

and we have to allocate these queued requests - 12 MB, 10 MB and 9 MB.

<u>First Fit Method -</u>

In the first fit process starts with the very first memory hole and it checks that memory should be allocated in the memory size as whole.

So that the First fit will be 20 MB, 10 MB, and 18 MB.

<u>Next Fit Method -</u>

  • Next Fit method works similarly to the first fit. the first step in both the methods is same. but in the next fit, in the second step it put the pointer on the previous allocated memory and then start allocating the next one just after that.
  • Advantage of next fit is you need not to search from the beginning again and again.

Thus, the allocation in next fit is 20 MB, 18 MB, and 9 MB.

<u>Best Fit Method -</u>

As the name tells, in this method it go thorough the entire list and tries to find the best allocation with minimal internal fragmentation.

Thus, the best fit allocation is 12 MB, 10 MB, and 9 MB.

<u>Worst Fit Method - </u>

  • The Worst fit method is totally opposite to the best fit method. in this method it tries to find the maximum internal fragmentation.
  • in best fit and the worst fit one thing is same that both the process search the entire list again and again.

So that, the allocation in worst fit will be 20 MB, 10 MB, and 15 MB.

I hope it worked for you!

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Explanation:

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Read 2 more answers
Complete function PrintPopcornTime(), with int parameter bagOunces, and void return type. If bagOunces is less than 3, print "To
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Answer:

<h2>Function 1:</h2>

#include <stdio.h> //for using input output functions

// start of the function PrintPopcornTime body having integer variable //bagOunces as parameter

void PrintPopcornTime(int bagOunces){

if (bagOunces < 3){ //if value of bagOunces is less than 3

 printf("Too small"); //displays Too small message in output

 printf("\n"); } //prints a new line

//the following else if part will execute when the above IF condition evaluates to //false and the value of bagOunces is greater than 10

else if (bagOunces > 10){

    printf("Too large"); //displays the message:  Too large in output

    printf("\n"); //prints a new line }

/*the following else  part will execute when the above If and else if conditions evaluate to false and the value of bagOunces is neither less than 3 nor greater than 10 */

else {

/* The following three commented statements can be used to store the value of bagOunces * 6 into result variable and then print statement to print the value of result. The other option is to use one print statement printf("%d",bagOunces * 6) instead */

    //int result;

    //result = bagOunces * 6;

    //printf("%d",result);

 printf("%d",bagOunces * 6);  /multiplies value of bagOunces  to 6

 printf(" seconds");

// seconds is followed with the value of bagOunces * 6

 printf("\n"); }} //prints a new line

int main(){ //start of main() function body

int userOunces; //declares integer variable userOunces

scanf("%d", &userOunces); //reads input value of userOunces

PrintPopcornTime(userOunces);

//calls PrintPopcornTime function passing the value in userOunces

return 0; }

Explanation:

<h2>Function 2:  </h2>

#include <stdio.h> //header file to use input output functions

// start of the function PrintShampooInstructions body having integer variable numCycles as parameter

void PrintShampooInstructions(int numCycles){

if(numCycles < 1){

//if conditions checks value of numCycles is less than 1 or not

printf("Too few."); //prints Too few in output if the above condition is true

printf("\n"); } //prints a new line

//else if part is executed when the if condition is false and else if  checks //value of numCycles is greater than 4 or not

else if(numCycles > 4){

//prints Too many in output if the above condition is true

printf("Too many.");

printf("\n"); } //prints a new line

//else part is executed when the if and else if conditions are false

else{

//prints "N: Lather and rinse." numCycles times, where N is the cycle //number, followed by Done

for(int N = 1; N <= numCycles; N++){

printf("%d",N);

printf(": Lather and rinse. \n");}

printf("Done.");

printf("\n");} }

int main() //start of the main() function body

{    int userCycles; //declares integer variable userCycles

   scanf("%d", &userCycles); //reads the input value into userCycles

   PrintShampooInstructions(userCycles);

//calls PrintShampooInstructions function passing the value in userCycles

   return 0;}

I will explain the for loop used in PrintShampooInstructions() function. The loop has a variableN  which is initialized to 1. The loop checks if the value of N is less than or equal to the value of numCycles. Lets say the value of numCycles = 2. So the condition evaluates to true as N<numCycles  which means 1<2. So the program control enters the body of loop. The loop body has following statements. printf("%d",N); prints the value of N followed by

printf(": Lather and rinse. \n"); which is followed by printf("Done.");

So at first iteration:

printf("%d",N); prints 1 as the value of N is 1

printf(": Lather and rinse. \n");  prints : Lather and rinse and prints a new line \n.

As a whole this line is printed on the screen:

1: Lather and rinse.

Then the value of N is incremented by 1. So N becomes 2 i.e. N = 2.

Now at second iteration:

The loop checks if the value of N is less than or equal to the value of numCycles. We know that the value of numCycles = 2. So the condition evaluates to true as N<numCycles  which means 2=2. So the program control enters the body of loop.

printf("Done."); prints Done after the above two lines.

printf("%d",N); prints 2 as the value of N is 2

printf(": Lather and rinse. \n");  prints : Lather and rinse and prints a new line \n.

As a whole this line is printed on the screen:

2: Lather and rinse.

Then the value of N is incremented by 1. So N becomes 2 i.e. N = 3.

The loop again checks if the value of N is less than or equal to the value of numCycles. We know that the value of numCycles = 2. So the condition evaluates to false as N<numCycles  which means 3>2. So the loop breaks.

Now the next statement is:

printf("Done."); which prints Done on the screen.

So as a whole the following output is displayed on the screen:

1: Lather and rinse.

2: Lather and rinse.

Done.

The programs along with their outputs are attached.

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Answer:

Explanation:

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}

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}

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}

total = dozen * 3.25 + (units * 45)/100;

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}

}

}

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